第6章实验5.5疑问
assume cs:codea segment
db 1,2,3,4,5,6,7,8 ...........定义的意思是A分别等于下列数，同时将A这个段放入内存了吗？
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
start: mov ax,a
mov ds,ax
mov ax,b
mov es,ax
mov bx,0
mov cx,8
s: mov al, 。。。。。。。。（al）=（ds：【bx】）~=（a：0）这个是将a:0放入al中，为啥al就等于a了。循环过程a又是怎么循环的呢？
add es:,al
inc bx
loop s
mov ax,c
mov ds,ax
mov bx,0
mov cx,8
s0: mov al,es:
mov ,al
inc bx
loop s0
mov ax,4c00h
int 21h
code ends
end start
assume cs:code
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
start:
mov cx,8
mov bx,0
s:
mov dl,0
mov ax,a
mov ds,ax
mov dl,ds:
mov ax,b
mov ds,ax
add dl,ds:
mov ax,c
mov ds,ax
mov ds:,dl
inc bx
loop s
code ends
end start
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