带你学C带你飞S1E45有疑问
#include <stdio.h>#include <stdlib.h>
struct Book
{
char title;
char author;
struct Book *next;
};
void getInput(struct Book *book);
void addBook(struct Book **library);
void printLibrary(struct Book *library);
void releaseLibrary(struct Book *library);
void getInput(struct Book *book)
{
printf("请输入书名:");
scanf("%s", book->title);
printf("请输入作者:");
scanf("%s", book->author);
}
void addBook(struct Book **library)
{
struct Book *book, *temp;
book = (struct Book *)malloc(sizeof(struct Book));
if (book == NULL)
{
printf("内存分配失败了!\n");
exit(1);
}
getInput(book);
if (*library != NULL)
{
temp = *library;
*library = book;
book->next = temp;
}
else
{
*library = book;
book->next = NULL;
}
}
void printLibrary(struct Book *library)
{
struct Book *book;
int count = 1;
book = library;
while (book != NULL)
{
printf("Book%d: \n", count);
printf("书名: %s\n", book->title);
printf("作者: %s\n\n", book->author);
book = book->next;
count++;
}
}
void releaseLibrary(struct Book *library)
{
while (library != NULL)
{
free(library);
library = library->next;
}
}
int main(void)
{
struct Book *library = NULL;
int ch;
while (1)
{
printf("请问是否需要录入书籍信息(Y/N):");
do
{
ch = getchar();
} while (ch != 'Y' && ch != 'N');
if (ch == 'Y')
{
addBook(&library);//这里和addBook(**library)是一样的么?
}
else
{
break;
}
}
printf("\n\n请问是否需要打印图书信息(Y/N):");
do
{
ch = getchar();
} while (ch != 'Y' && ch != 'N');
if (ch == 'Y')
{
printLibrary(library);
}
releaseLibrary(library);
return 0;
}
第24行和第90行为什么不一样呢?第90行要是写成addBook(**library)会报错,(**library)和(&library)不都是取指针的地址的意思么? (**library)和(&library) 我觉得这两个是不一样的,首先&library 是取指针变量library 地址是对的,但
**library 不是取指针变量library地址,library 首先是一个指针变量,*library就是取library所指向内存里的值,在此程序中library = NULL,就是空指针,没有指向那个具体的值,此时再去用‘*’取 一个空值是没有意义的,就像这样*(*library])= * (NULL),这样是没有意义的. 参数为 *library 我们要传入的 是一个变量的地址 , 如果参数为 **library 那么我们就要传入一个指针的地址
*library是一个指针 ,**library是一个指向指针的指针{:10_256:} qq1242009750 发表于 2017-4-15 10:24
参数为 *library 我们要传入的 是一个变量的地址 , 如果参数为 **library 那么我们就要传入一个指针的地址 ...
终于明白了,感谢您的回复!
页:
[1]