Python：每日一题 29（答题领鱼币）
感谢冬雪的题目！！！python有分数类型和相应的计算方法，要求不用分数模块（真是见鬼！）编写一个简单的分数加法和减法函数，实现分数与分数，分数与整数的加减法。如
3/5 - 1/5 = 2/5
1/2 - 1/3 = 1/6
1/2 + 1/2 = 1
1- 1/3 = 2/3
函数的用法
add(a, b, c, d)
a, b为第一个分数的分子与分母
c, d 为第二个分数的分子与分母
减法类似。
给大家不符合规则的：
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{:10_248:} 帅的人都上车了，而丑的人还在犹豫{:10_248:} #!/usr/bin/env python2
# -*- coding: utf-8 -*-
"""
Created on Sun Apr 16 09:45:31 2017
@author: jerry_xu
"""
def fadd(a,b,c,d):
fenzi = a*d+b*c
fenmu = b*d
GCD = lambda x,y:x if y==0 else GCD(y, x%y)
gcd = GCD(fenzi,fenmu)
fenzi /= gcd
fenmu /= gcd
return fenzi, fenmu
print '1/6 + 1/3 = %d/%d' % fadd(1,6,1,3)
def fminus(a,b,c,d):
fenzi = a*d-b*c
fenmu = b*d
GCD = lambda x,y:x if y==0 else GCD(y, x%y)
gcd = GCD(fenzi,fenmu)
fenzi /= gcd
fenmu /= gcd
return fenzi, fenmu
print '1/2 - 1/3 = %d/%d' % fminus(1,2,1,3)
输出：
1/6 + 1/3 = 1/2
1/2 - 1/3 = 1/6 看看不符合规则的 ooxx7788 发表于 2017-4-16 10:27
看看不符合规则的
{:10_262:} #!/usr/bin/env python2
# -*- coding: utf-8 -*-
"""
Created on Sun Apr 16 09:45:31 2017
@author: jerry_xu
"""
def fadd(a,b,c,d):
fenzi = a*d+b*c
fenmu = b*d
GCD = lambda x,y:x if y==0 else GCD(y, x%y)
gcd = GCD(fenzi,fenmu)
fenzi /= gcd
fenmu /= gcd
return fenzi, fenmu
print '1/6 + 1/3 = %d/%d' % fadd(1,6,1,3)
def fminus(a,b,c,d):
fenzi = a*d-b*c
fenmu = b*d
GCD = lambda x,y:x if y==0 else GCD(y, x%y)
gcd = GCD(fenzi,fenmu)
fenzi /= gcd
fenmu /= gcd
return fenzi, fenmu
print '1/2 - 1/3 = %d/%d' % fminus(1,2,1,3) 没看懂题目
def my_add(a,b,c,d):
return a/b+c/d
感觉这个就能实现了 奔跑的小鱼 发表于 2017-4-17 11:40
没看懂题目
def my_add(a,b,c,d):
return a/b+c/d
返回的需要是分数 又看了下,看懂题目了
def Dicisor(a,b):
#最大公约数
dicisor_list =
return max(dicisor_list)
def my_add(a,b,c,d):
molecular = a*d +c*b
denominator =b*d
result = molecular/denominator
if result == int(result):
print(int(result))
else:
dicisor = Dicisor(molecular,denominator)
molecular_new = int(molecular/dicisor)
denominator_new = int(denominator/dicisor)
print("%s/%s"%(molecular_new,denominator_new)) zhhmms 发表于 2017-4-17 08:59
#!/usr/bin/env python2
# -*- coding: utf-8 -*-
"""
你这个递归用的牛 冬雪雪冬 发表于 2017-4-17 11:57
返回的需要是分数
{:7_114:}看懂了,楼下是我的答案 本帖最后由 余欲渔 于 2017-4-17 15:48 编辑
ab=input('请输入需要计算的分式,如1/5-2/8:')
f=0
def yf(aa,bb):
for i in range(aa,1,-1):
if (aa/i)%1==0 and (bb/i)%1==0:
aa=int(aa/i)
bb=int(bb/i)
break
if bb>1:
return str(aa)+r'/'+str(bb)
else :return str(aa)
def jg(a1,a2,b1,b2):
if f:
aa=a1*b2+a2*b1
else:
aa=a1*b2-a2*b1
bb=a2*b2
return yf(aa,bb)
if '-'in ab:
a,b=ab.split(sep='-')
elif '+'in ab:
a,b=ab.split(sep='+')
f=1
else :
print('输入错误')
try:
a1,a2=
except:
a1=int(a)
a2=1
try:
b1,b2=
except:
b1=int(b)
b2=1
print(jg(a1,a2,b1,b2))
看看不符合规则的
应该要用到最大公约数来约分，还要判断一次是不是整数
def gcd(m,n):
"""辗转相除法，寻找n和m的最大公约数"""
# 本来还想分大小，结果发现不分也可以，因为会换过来
while n != 0:
m,n = n, m%n
return m
# 用公倍数处理，再除以最大公约数就可以相加了 (a*d)/(b*d) + (c*b)/(d*b)
def fractional_add(a,b,c,d):
"""分数加法，a/b + c/d """
numerator = a*d + c*b # 分子
denominator = b*d # 分母
if numerator % denominator == 0:
# 整除情况下打印整数
print(numerator // denominator)
else:
divisor = gcd(numerator, denominator)
print("%d / %d" % (numerator/divisor, denominator/divisor))
def fractional_minus(a,b,c,d):
"""分数减法, a/b - c/d"""
numerator = a*d - c*b
denominator = b*d
if numerator % denominator == 0:
# 整除情况下打印整数
print(numerator // denominator)
else:
divisor = gcd(numerator, denominator)
print("%d / %d" % (numerator/divisor, denominator/divisor)) 看看 def yf(m,n):
for i in range(2,m):
if m%i == 0 and n%i == 0:
m,n = m//i,n//i
yf(m,n)
return m,n
def add(a, b, c, d):
x = b*d
y = a*d
z = c*b
count = 0
s = y + z
s,x = yf(s,x)
print('%s/%s'%(s,x)) def add_f(a,b,c,d):
e = a*d+b*c
f = b*d
return e ,f
def sub_f(a,b,c,d):
e = a*d-b*c
f = b*d
return e ,f from __future__ import division
# Get a and b 's the Maximum common divisor
def Max_Common_Divisor(a, b):
while b != 0:
c = a % b
a = b
b = c
return a# a is max common divisor
# Get a and b's the least common multiple
def Min_Common_Multiple(a, b):
return a * b / a
# Fractional Addition
# a is the first fraction's molecular, b is the first fraction's Denominator
# c is the second fraction's molecular, d is the second fraction's Denominator
# return the molecular and Denominator of Fraction_Add_Fraction's Add and Minus
def Add_Minus_Of_Fraction_Fraction(a, b, c, d):
list = []
New_Multiple = Min_Common_Multiple(b, d)
b_Business = New_Multiple / b
d_Business = New_Multiple / d
a = a * b_Business
c = c * d_Business
# Get Add of Fractions
Add_Molecular = a + c
Add_Divisor = Max_Common_Divisor(New_Multiple, Add_Molecular)
list.append(int(Add_Molecular / Add_Divisor))
list.append(int(New_Multiple / Add_Divisor))
# Get Minus of Fractions
Minus_Molecular = a - c
Minus_Divisor = Max_Common_Divisor(New_Multiple, Minus_Molecular)
list.append(int(Minus_Molecular / Minus_Divisor))
list.append(int(New_Multiple / Minus_Divisor))
print "%d/%d + %d/%d = %d/%d" % (a, b, c, d, list, list)
print "%d/%d - %d/%d = %d/%d" % (a, b, c, d, list, list)
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