python：每日一题 33,Python交流,技术交流,鱼C论坛

天天学习$ 发表于 2018-4-17 20:17:31

本帖最后由天天学习$ 于 2018-4-17 20:21 编辑

def tickets(people):
i = 0
for temp in people:
   if (temp - 25) == 0 or (temp - 25) <= (i * 25) :
         pass

   else:
         return 'no'
         break
   i += 1
return 'yes'

萧丹夜 发表于 2018-5-26 21:23:09

貌似可行

def Booking(x):
y ={100:0,50:0,25:0}
for each in x:
   if each == 100:
         y += 1
         if y >= 1 and y >= 1:
            y -= 1
            y -= 1
         elif y >= 3:
            y -= 3
         else:
            break
   elif each == 50:
         y += 1
         if y >= 1:
            y -= 1
         else:
            break
   elif each == 25:
         y += 1
   else:
         return '输入有误！'
else:
   return 'yes'
return 'no'

x = list(map(int,input('请输入排队购票金额：').split()))
result = Booking(x)
print(result)

475123763 发表于 2018-7-16 23:24:51

a =
n25 = 0
n50 = 0
n100 = 0
for i in range(0,6):
if a == 25:
n25 = n25 + 1
if i == 6:
print("yes")
if a == 50:
n50 = n50+1
if n25 > 0:
      n25 = n25-1
else:
      print("no")
if a == 100:
if n50>0:
   n50 = n50 -1
if n25>2:
      n25 = n25 -3
else:
      print('no')
自己这个程序有问题，感觉自己写的好累，还是要多加油

小强工作室 发表于 2018-8-1 14:33:38

学习一下

jrro452 发表于 2018-8-23 16:45:52

看看楼主的方法

jrro452 发表于 2018-8-23 16:46:53

def tickets(people):
ticketmoney ={'25':0,'50':0,'100':0}
x=0
for i in range(len(people)):
   x+=1
   if people != 25:
         return 'No'
         break
   ticketmoney)]+=1
   if people==50:
         if ticketmoney['25']>=1:
            ticketmoney['25']-=1
         else:
            return 'No'
            break
   if people==100:
         if ticketmoney['50']==0 and ticketmoney['25']>=3:
            ticketmoney['25']-=3
         elif ticketmoney['25']>1 and ticketmoney['50']>=1 :
            ticketmoney['25']-=1
            ticketmoney['50']-=1
         else:
            return 'No'
            break
   if x==len(people):
         return 'Yes'
people =
print(tickets(people))
结果“Yes”

jiaozhu80 发表于 2018-9-2 21:09:12

本帖最后由 jiaozhu80 于 2018-9-3 12:08 编辑

def ticket(people):
price_dict={25:0,50:0}
result=[]
for i in range(len(people)):
   if people==25:
         result.append("yes")
         price_dict+=1
   elif people==50:
         if price_dict>1 or price_dict==1:
            result.append("yes")
            price_dict-=1
            price_dict+=1
         else:
            result.append("no")
   elif people==100:
         if (price_dict*price_dict>=1)or (price_dict==3):
            result.append("yes")
            if price_dict>=1:
               price_dict-=1
               price_dict-=1
            else:
               price_dict-=3
         else:
            result.append("no")
print(price_dict,price_dict,result)

if "no" not in result:
   return "yes"
else:
   return "no"

jiaozhu80 发表于 2018-9-2 21:12:53

您好：请问if __name__=="__main__":表示什么意思？

算幽幽 发表于 2018-9-25 22:55:17

I love Fishc
def tickets(people):

count=0
for i in people:
   sum=count*25
   ifi-sum>25 or(i-sum)%25!=0:
         print(i,sum)
         return 'no'
   count += 1

else:
   print(i, sum)
   return 'yes'

print(tickets())

算幽幽 发表于 2018-9-25 23:00:15

算幽幽发表于 2018-9-25 22:55
I love Fishc

还是有问题

lyslyslys 发表于 2018-9-27 13:41:11

感谢

double-lee 发表于 2018-12-11 16:29:54

def tickets(people):
total = {25:0,50:0,100:0}

for i in range(len(people)):
   if i == 0 and people != 25:
         return 'no'
   elif people == 50 and total == 0:
         return 'no'
   elif people == 25:
         total += 1
   elif people == 50 and total >= 1:
         total -= 1
         total += 1
   elif people == 100:
         if total == 0 and total < 3:
            return 'no'
         elif total > 0 and total == 0:
            return 'no'
         elif total == 0 and total >= 3:
            total += 1
            total -= 3
         elif total > 0 and total > 0:
            total += 1
            total -= 1
            total -= 1
else:
   return 'yes'
新手小白把可能的情况都列出来了。。。{:5_107:}

3333332 发表于 2019-2-27 10:14:44

谢谢

不忘初心1020 发表于 2019-2-27 10:23:08

无处不编程

yu123py 发表于 2019-4-30 21:53:02

给我鱼币！
def faulty_odometer(i):
c = 0
j = 1
while j <= i:
   if '4' in str(j):
         jump = 10 ** (len(str(j)) - str(j).index('4') - 1)
         c += jump
         j += jump
   j += 1
return i - c

panheng 发表于 2019-8-23 10:29:26

def tickets(custom):
for each in custom:
   change = each - 25
   if change == 0:                            #不用找钱
         dict1['25'] += 1
   elif change == 75:                         #找75块
         if dict1['50'] > 0 and dict1['25'] > 0:
            dict1['50'] -= 1
            dict1['25'] -= 1
            dict1['100'] += 1
         elif dict1['25'] >= 3:
            dict1['25'] -= 3
            dict1['100'] += 1
         else:
            return False
   else:                                     #找25块
         if dict1['25'] >0:
            dict1['25'] -= 1
            dict1['50'] += 1
         else:
            return False
else:
   return True

if __name__ == '__main__':
dict1 = {'100': 0, '50': 0, '25': 0}                #初始资金池
str1 = input('请输入每人放入的金额面值，以“，”分隔')
custom =
result = tickets(custom)
print(result)
if result:
   print(dict1)

克里斯保罗 发表于 2019-9-4 17:27:41

import test
def tickets(people):
      temp = []
      temp.append(25)
      length = len(people)
      if people!=25:
                           return 'NO'
      for each in range(1,length):
               ch= people - 25
               if ch == 0:
                           temp.append(people)
               else:
                           if people == 100:
                                    if 25 in temp and 50 in temp:
                                             temp.remove(25)
                                             temp.remove(50)
                                             temp.append(100)
                                    else:
                                             return 'NO'
                           elif people == 50:
                                    if 25 not in temp:
                                             return 'NO'
                                    else:
                                             temp.remove(25)
                                             temp.append(50)

      return 'YES'

test.assert_equals(tickets(), 'YES')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'YES')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'YES')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'YES')
test.assert_equals(tickets(),'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')
test.assert_equals(tickets(), 'NO')

杜若左 发表于 2020-4-1 17:59:46

gopythoner 发表于 2017-4-25 20:17
我写了一个，把你上面的测试了，全部正确

大佬，牛皮。你的是我看道最简洁易懂的。谢谢

holiday_python 发表于 2020-4-19 18:29:50

19971023 发表于 2020-6-5 17:32:35

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