请教大家，为什么python中isalpha()函数会把汉字判定为字母？
零基础学习python19课练习题def count(*param):
length = len(param)
for i in range(length):
letters = 0
space = 0
digit = 0
other = 0
for each in param:
if each.isalpha():
letters += 1
elif each.isdigit():
digit += 1
elif each ==" ":
space += 1
else:
other += 1
print("第%d个字符串有：英文字母%d个，空格%d个,数字%d个，其他字符%d个"%(i+1,letters,space,digit,other))
count("汉字") 对于unicode string，string.isalpha会根据字符串中的字符是否属于Unicode编码的LETTER区域来判断是否都由字母组成。所以得出的结果为True，不一定表示只有26个英文字母。
def count(*param):
length = len(param)
for i in range(length):
letters = 0
space = 0
digit = 0
other = 0
for each in param:
print(each)
if each.encode('UTF-8').isalpha():
letters += 1
elif each.encode('UTF-8').isdigit():
digit += 1
elif each ==" ":
space += 1
else:
other += 1
print("第%d个字符串有：英文字母%d个，空格%d个,数字%d个，其他字符%d个"%(i+1,letters,space,digit,other))
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