Python：每日一题85（答题领鱼币）,Python交流,技术交流,鱼C论坛

冬雪雪冬 发表于 2017-8-25 12:29:51

Python：每日一题85（答题领鱼币）

题目：
编写一个字符串处理函数，1）如果输入的字符串不包含元音字母（aeiouAEIOU）则输出这个字符且首字符小写其他大写；2）如果输入的字符串包含元音字母，则输入这个字符串且首个元音字母后面紧跟的一个辅音字母（非aeiouAEIOU）大写，其他小写，如果是连续元音字母则后推到后面第一个辅音字母；3）如果输入的字符串包含元音字母，按照2）无法找到辅音字母则输出这个字符串且全体大写。
def fun(string):
pass

print(fun('str'))
print(fun('FishC'))
print(fun('boolean'))
print(fun('too'))

sTR
fiShc
booLean
TOO

楼主的解法：
**** Hidden Message *****

jerryxjr1220 发表于 2017-8-25 13:23:40

耍宝写法，return嵌套
def fun(string):
string = string.lower()
return string+string.upper() if not set(string)&set('aeiou') else (string.upper() if set(string)<=set('aeiou') else +string.upper()+string for i in range(1, len(string)-1) if string in 'aeiou' and string not in 'aeiou'])

bush牛 发表于 2017-8-25 18:39:23

def fun(string):
s = string.lower()
flag = 0 #没有元音
y = 0 #存放连续元音最后一个的索引
for (i,j) in zip(s, range(len(s))):
   if i in 'aeiou':
         if j == len(s)-1:
            flag = 1 #元音在最后的位置
         elif j+2 <= len(s):
            if s in 'aeiou':
               continue
            else:
               y = j # 有连续元音
               flag = 2
               break

if flag == 0:
   s = s + s.upper()
elif flag == 1:
   s = s.upper()
elif flag == 2:
   s = s[:y+1] + s.upper() + s
return s

solomonxian 发表于 2017-8-25 19:09:20

3种情况：1、无元音
         2.1、元音后有辅音
         2.2、元音后无辅音
用re，找元音后第一个辅音
import re

def fun(string):
s = string.lower()
if set(s).intersection(set("aeiou")):
   m = re.search(r"(?<=)[^aeiou]", s)
   return s[:m.start()]+s.capitalize() if m else s.upper()
else:
   return s.capitalize().swapcase()
如果不用 re 的话
我想先找出所有辅音，然后用字母外的东东拼长，
再与原string对比，,元素不同且不为元音的就是目标，取其索引
def fun2(string):
s = string.lower()
cons =
nums = {k for i,j,k in zip(cons+list('。'*len(s)),s,range(len(s))) if i!=j and j not in "aeiou"}

if cons == list(s):
   return s.capitalize().swapcase()
else:
   return s[:min(nums)]+s.capitalize() if nums else s.upper()

chunchun2017 发表于 2017-8-26 19:03:47

def fun(str0):
index0 = -1
index1 = -1
for i in str0:
   if(i in ('aeiouAEIOU')):
      index0 = str0.index(i)
      for j in str0:
         if(j not in ('aeiouAEIOU')):
            index1 = str0.index(j)
            break
      break
if(index0 == -1):
   return str0.lower()+str0.upper()
elif (index1!=-1):
   return str0.lower()+str0.upper()+str0.lower()
else:
   return str0.upper()
str0=input('请输入一个字符串:')
print(fun(str0))
运行结果：
>>>
============== RESTART: C:\Users\每日一题\85.py==============
请输入一个字符串:str
sTR
>>>
============== RESTART: C:\Users\每日一题\85.py==============
请输入一个字符串:FishC
fiShc
>>>
============== RESTART: C:\Users\每日一题\85.py==============
请输入一个字符串:boolean
booLean
>>>
============== RESTART: C:\Users\每日一题\85.py ==============
请输入一个字符串:too
TOO

BeginnerSK 发表于 2017-8-28 22:24:58

l1993520 发表于 2017-8-29 00:54:44

def fun():
str1 = input('请输入：')
for x in str1:
   if x in 'aeiouAEIOU':
         if str1.endswith(x):
            return str1.upper()
         for t in range(str1.find(x)+1, len(str1)):
            if str1 not in 'aeiouAEIOU':
               return str1[:t].lower() + str1.upper() + str1.lower()
         else:
            return str1.upper()
return str1.lower() + str1.upper()

print(fun())

wyp02033 发表于 2017-8-30 16:10:14

def is_vowel(s):
if s.lower() in 'aeiou':
   return True
else:
   return False

def fun(string):
string = string.lower()
i = 0
while i < len(string):
   if is_vowel(string) and not is_vowel(string):
         return string[:i+1] + string.upper() + string
   else:
         i += 1
         if i == len(string)-1 and is_vowel(string):
            return string.upper()
else:
   return string + string.upper()

AKA2pac 发表于 2017-9-16 13:55:26

def fun(string):
string = string.lower()
return string+string.upper() if not set(string)&set('aeiou') else (string.upper() if set(string)<=set('aeiou') else +string.upper()+string for i in range(1, len(string)-1) if string in 'aeiou' and string not in 'aeiou'])

shigure_takimi 发表于 2017-12-5 09:29:33

yuanYin = 'aeiouAEIOU'
fuYin = 'bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ'

def hasYuanyin(string):
for char in string:
   if char in yuanYin:
         return True
return False

def fun(string):
if not hasYuanyin(string):
   s =
   s = s.lower()
   return ''.join(s)
else:
   length = len(string)
   s =
   startYuanyin = 0# 起始元音位置
   continuousYuanyin = 0 # 首个元音后连续元音个数(含首个元音）
   startFuyin = 0
   for i in range(length):
         if s in yuanYin:
            startYuanyin = i
            break
   if startYuanyin == length - 1:
         return string.upper()
   else:
         for i in range(startYuanyin, length):
            if s in yuanYin:
               continuousYuanyin += 1
            else:
               break
         startFuyin = startYuanyin + continuousYuanyin
         if startFuyin == length:
            return string.upper()
         else:
            s = s.upper()
            return ''.join(s)

print(fun('str'))
print(fun('FishC'))
print(fun('boolean'))
print(fun('too'))
print(fun('jkjkjkljljlo'))

sTR
fiShc
booLean
TOO
JKJKJKLJLJLO

yjsx86 发表于 2018-1-29 10:54:29

def func(string):
check = 'aeiouAEIOU'
for i in range(len(string)):
   if string in check and i == len(string)-1:
         return string.upper()
   elif string in check and string not in check:
         return string[:i+1].lower()+string.upper()+string.lower()
else:
   return string.lower()+string.upper()

咕咕鸡鸽鸽 发表于 2019-2-28 17:44:25

kankan

咕咕鸡鸽鸽 发表于 2019-2-28 17:45:26

本帖最后由咕咕鸡鸽鸽于 2019-3-2 13:48 编辑

。

咕咕鸡鸽鸽 发表于 2019-2-28 17:46:33

本帖最后由咕咕鸡鸽鸽于 2019-3-2 13:48 编辑

。

咕咕鸡鸽鸽 发表于 2019-2-28 17:48:10

def fun85(str1):
vowel = ["a","e","i","o","u"]
alive = False
for each in str1:
   if each.lower() in vowel:
         alive = True
         index = str1.index(each)
         break

if alive:
   while str1 in vowel:
         index += 1
         if index == len(str1)-1:
            return str1.upper()
   return str1[:index+1].lower() + str1.upper() + str1.lower()
else:
   return str1.lower() + str1.upper()

print(fun85("str"))
print(fun85("FishC"))
print(fun85("boolean"))
print(fun85("too"))

Geoffreylee 发表于 2020-3-17 14:06:58

import re

def f_85(string: str) -> str:
if not re.match(r'.*.*', string):
   return string.lower() + string.upper()
else:
   first_vowels = re.search(r'+', string)
   consonants = re.split(first_vowels.group(), string)
   if consonants == '':
         return string.upper()
   else:
         return consonants.lower() + first_vowels.group().lower() + consonants.capitalize()

print(f_85('aOOl'))

Geoffreylee 发表于 2020-3-17 14:09:34

小陨aoq 发表于 2020-7-31 19:54:08

def fun(string):
vowel_list = ["a", "e", "i", "o", "u"]
string = string.lower()

last_char = "c"
result = 0

for s in string:
   # 查找[元音+辅音]的组合
   if (s not in vowel_list) and (last_char in vowel_list):
         # 找到后返回辅音的下标
         result = string.find(s)
         break
   else:
         last_char = s

if result:
   # 存在[元音+辅音]的组合
   return string[:result] + string.capitalize()
   print(result)
elif last_char in vowel_list:
   # 没有[元音+辅音]的组合，但有元音
   return string.upper()
else:
   # 没有元音
   return string.capitalize().swapcase()

19971023 发表于 2020-8-4 10:07:26

aironeng 发表于 2020-12-9 08:46:04

学习

页: [1] 2

鱼C论坛's Archiver

Python：每日一题85（答题领鱼币）