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发表于 2022-11-8 14:44:39
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本楼为最佳答案
这样?- a = 'fg=5d21d74472eacda102331f1;Name=CHGCD04F1229119B2E3B9F9;\nfg=5GT64J8LKFGR6FEC288A82E09FDED4B21C65C0C84538CF4573044D7C1BEA65DA684E0BE04B70852; Name=6Ydd884RTGD3157f40394f;\rfg=7d2102331f1;Name=CHGCD04F1229119B2E3B9F9;\n\rfg=..'
- re.findall('(.*?[\n\r]+)', a, re.M)
- ['fg=5d21d74472eacda102331f1;Name=CHGCD04F1229119B2E3B9F9;\n', 'fg=5GT64J8LKFGR6FEC288A82E09FDED4B21C65C0C84538CF4573044D7C1BEA65DA684E0BE04B70852; Name=6Ydd884RTGD3157f40394f;\r', 'fg=7d2102331f1;Name=CHGCD04F1229119B2E3B9F9;\n\r']
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