论坛 › Python交流 › Python：每日一题 133

321123 发表于 2018-1-7 12:04:32

或者把for循环里面的部分变为：list3=list(set(list2))
list3.sort()

yjsx86 发表于 2018-1-8 04:21:07

l = [
    12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16,
    19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18,
    16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12,
    2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5,
    1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3
]

d = dict.fromkeys(set(l), 0)
rs = []

for x in l:
    d += 1

for k, v in d.items():
    rs.append()

print(rs)

我也爱鱼c 发表于 2018-1-8 19:25:40

list1 =
list_ = []
list4 = []
def count_(i):
    for i in list1:
      a = list()
      list_.append(a)
      list_.sort()
    list2 = list_
    for n in list2:
      if n not in list4:
            list4.append(n)      
    return list4   
count1 = count_(12)
print(count1)
用的最笨的方法，回复只是先看看其他大神的答案

我也爱鱼c 发表于 2018-1-8 19:29:11

在哪里看最佳答案？

lihw 发表于 2018-1-8 20:20:01

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18,
         2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0,
         0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1,
         12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2,
         9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15,
         3, 16, 20, 18, 4, 18, 16, 3]
list2=[]
list3=[]
n=0
list2=set(list1)
for i in list2:
    n=list1.count(i)
    list3.append()
print(list3)

mjhpython 发表于 2018-1-8 20:57:28

l_chongdu = []
l = []
l1 =
for num in l1:
    if num not in l_chongdu:
      l_chongdu.append(num)
      l.append()
print sorted(l)

sunnychou 发表于 2018-1-10 11:19:58

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17,
6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16,
17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
a = collections.Counter(list1)
c =
b =
a = list(zip(c, b))#实现排序，根据key值排序
a.sort()
print()

vite 发表于 2018-1-10 13:30:55

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3,
         18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0,
         12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4,
         14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12,
         18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1,
         13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
list2 = [ for a in range (max(list1)+1) if a in list1 ]

lampard0810 发表于 2018-1-10 14:33:30

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6,\
         16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, \
         18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7,\
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14,\
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, \
         18, 16, 3]
result = []

list1_differ = list(set(list1))#去掉列表中的重复项
list1_differ.sort()#对新生成的列表进行排序
for each in list1_differ:
    result.append()

print(result)

yun212 发表于 2018-1-10 15:48:09

111111111

likesunshine 发表于 2018-1-10 16:21:40

想知道代码

wojiaodabai 发表于 2018-1-10 16:26:40

list1 =       

myset=set(list1)
list2=[[] for x in range(len(myset))]

for i in myset:
    list2.append()
   
print(list2)

一绿一整周 发表于 2018-1-10 16:52:21

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10,
         6, 10, 0, 4, 3, 18, 2, 18, 17, 6,
         16, 19, 12, 18, 4, 4, 16, 12, 13,
         11, 0, 0, 12, 7, 10, 2, 7, 12, 4,
         18, 13, 18, 16, 17, 14, 12, 1, 12,
         4, 14, 8, 18, 4, 12, 10, 1, 18, 7,
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
         15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10,
         0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]

print(len(list1))
print(max(list1))
list2_d=
for l in range(0,max(list1)+1):
    n=0
    for i in range(0,len(list1)):
      if list1 == l:
             n=n+1
      else :
             n=n
    list2_d=list()
    if l !=20:
      list2_d.append()
    else:
      break
print(list2_d)
   

一绿一整周 发表于 2018-1-10 17:04:58

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10,
         6, 10, 0, 4, 3, 18, 2, 18, 17, 6,
         16, 19, 12, 18, 4, 4, 16, 12, 13,
         11, 0, 0, 12, 7, 10, 2, 7, 12, 4,
         18, 13, 18, 16, 17, 14, 12, 1, 12,
         4, 14, 8, 18, 4, 12, 10, 1, 18, 7,
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
         15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10,
         0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]

list2_d =
for i in range(max(list1)):
    m = list1.count(i)
    list2_d=list()
    if i != 20:
      list2_d.append()
    else:
      pass
print(list2_d)

Jons 发表于 2018-1-10 17:32:48

list1 =

#先去重函数用 list(set(list1)) 排序函数用sorted()结果输出结果是：
lists = sorted(list(set(list1)))
listData = []
for i,n in enumerate(lists):
    #查询有个值在列表中出现的次数函数
    listData.append()

print('输出结果是:',listData)

#输出结果是: [, , , , , , , , , , , , , , , , , , , , ]

wenjiew 发表于 2018-1-10 17:48:24

本帖最后由 wenjiew 于 2018-1-10 17:49 编辑

from collections import defaultdict
def solutions(list1):
        list2 = defaultdict(int)
        for elements in list1:
                list2 += 1
        return

wenjiew 发表于 2018-1-10 17:49:22

wenjiew 发表于 2018-1-10 17:48
def solutions(list1):
        list2 = defaultdict(int)
        for elements in list1:


在开头加一个from collections import defaultdict

张仙东 发表于 2018-1-10 18:57:22

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4,
         14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]


list2 = list(set(list1))
list2.sort()
arr = [ for x in list2]
print(arr)

libiao 发表于 2018-1-10 20:49:39

list1 =
max1 = max(list1)
min1 = min(list1)
a=[]
c=[]
for i in list1:
    b = list1.count(i)
    a.append(b)
for each in list1:
    if each not in c:
      c.append(each)
d = list(map(lambda x,y:,c,a))
d.sort()
print(d)

libiao 发表于 2018-1-10 20:52:18

list1 =
a=[]
c=[]
for i in list1:
    b = list1.count(i)
    a.append(b)
for each in list1:
    if each not in c:
      c.append(each)
d = list(map(lambda x,y:,c,a))
d.sort()
print(d)

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