Python：每日一题 133

321123

或者把for循环里面的部分变为：list3=list(set(list2))
list3.sort()

yjsx86

1. l = [
   
2.     12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16,
   
3.     19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18,
   
4.     16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12,
   
5.     2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5,
   
6.     1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3
   
7. ]
   
8. 
   
9. d = dict.fromkeys(set(l), 0)
   
10. rs = []
    
11. 
    
12. for x in l:
    
13.     d[x] += 1
    
14. 
    
15. for k, v in d.items():
    
16.     rs.append([k, v])
    
17. 
    
18. print(rs)

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我也爱鱼c

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
list_ = []
list4 = []
def count_(i):
    for i in list1:
        a = list([i,list1.count(i)])
        list_.append(a)
        list_.sort()
    list2 = list_
    for n in list2:
        if n not in list4:
            list4.append(n)        
    return list4   
count1 = count_(12)
print(count1)
用的最笨的方法，回复只是先看看其他大神的答案

我也爱鱼c

在哪里看最佳答案？

lihw

1. list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18,
   
2.          2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0,
   
3.          0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1,
   
4.          12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2,
   
5.          9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
   
6.          18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15,
   
7.          3, 16, 20, 18, 4, 18, 16, 3]
   
8. list2=[]
   
9. list3=[]
   
10. n=0
    
11. list2=set(list1)
    
12. for i in list2:
    
13.     n=list1.count(i)
    
14.     list3.append([i,n])
    
15. print(list3)
    

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mjhpython

l_chongdu = []
l = []
l1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
for num in l1:
    if num not in l_chongdu:
        l_chongdu.append(num)
        l.append([num,l1.count(num)])
print sorted(l)

sunnychou

1. list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17,
   
2. 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16,
   
3. 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
   
4. 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
   
5. a = collections.Counter(list1)
   
6. c = [i for i in a.keys()]
   
7. b = [i for i in a.values()]
   
8. a = list(zip(c, b))#实现排序，根据key值排序
   
9. a.sort()
   
10. print([list(i) for i in a])

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vite

1. list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3,
   
2.          18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0,
   
3.          12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4,
   
4.          14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12,
   
5.          18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1,
   
6.          13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
   
7. list2 = [[a,list1.count(a)] for a in range (max(list1)+1) if a in list1 ]

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lampard0810

1. list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6,\
   
2.          16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, \
   
3.          18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7,\
   
4.          2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14,\
   
5.          18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, \
   
6.          18, 16, 3]
   
7. result = []
   
8. 
   
9. list1_differ = list(set(list1))#去掉列表中的重复项
   
10. list1_differ.sort()#对新生成的列表进行排序
    
11. for each in list1_differ:
    
12.     result.append([each,list1.count(each)])
    
13. 
    
14. print(result)

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yun212

111111111

likesunshine

想知道代码

wojiaodabai

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]        

myset=set(list1)
list2=[[] for x in range(len(myset))]  

for i in myset:
    list2[i].append([i,list1.count(i)])
   
print(list2)

一绿一整周

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10,
         6, 10, 0, 4, 3, 18, 2, 18, 17, 6,
         16, 19, 12, 18, 4, 4, 16, 12, 13,
         11, 0, 0, 12, 7, 10, 2, 7, 12, 4,
         18, 13, 18, 16, 17, 14, 12, 1, 12,
         4, 14, 8, 18, 4, 12, 10, 1, 18, 7,
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
         15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10,
         0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]

print(len(list1))
print(max(list1))
list2_d=[0]
for l in range(0,max(list1)+1):
    n=0
    for i in range(0,len(list1)):
        if list1[i] == l:
             n=n+1
        else :
             n=n
    list2_d[l]=list([l,n])
    if l !=20:
        list2_d.append([l,n])
    else:
        break
print(list2_d)
   

一绿一整周

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10,
         6, 10, 0, 4, 3, 18, 2, 18, 17, 6,
         16, 19, 12, 18, 4, 4, 16, 12, 13,
         11, 0, 0, 12, 7, 10, 2, 7, 12, 4,
         18, 13, 18, 16, 17, 14, 12, 1, 12,
         4, 14, 8, 18, 4, 12, 10, 1, 18, 7,
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18,
         15, 1, 9, 5, 11, 6, 12, 9, 16, 14,
         18, 0, 15, 4, 17, 5, 1, 13, 0, 10,
         0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]

list2_d = [0]
for i in range(max(list1)):
    m = list1.count(i)
    list2_d[i]=list([i,m])
    if i != 20:
        list2_d.append([i,m])
    else:
        pass
print(list2_d)

Jons

1. 
   
2. list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
   
3. 
   
4. #先去重函数用 list(set(list1)) 排序函数用sorted()  结果输出结果是：[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
   
5. lists = sorted(list(set(list1)))
   
6. listData = []
   
7. for i,n in enumerate(lists):
   
8.     #查询有个值在列表中出现的次数函数
   
9.     listData.append([n,list1.count(n)])
   
10. 
    
11. print('输出结果是:',listData)
    
12. 
    
13. #输出结果是: [[0, 7], [1, 6], [2, 4], [3, 5], [4, 8], [5, 2], [6, 4], [7, 3], [8, 2], [9, 4], [10, 5], [11, 3], [12, 11], [13, 4], [14, 3], [15, 3], [16, 8], [17, 3], [18, 11], [19, 3], [20, 1]]
    

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wenjiew

from collections import defaultdict
def solutions(list1):
        list2 = defaultdict(int)
        for elements in list1:
                list2[elements] += 1
        return [item for item in sorted(list2.items())]

wenjiew

wenjiew 发表于 2018-1-10 17:48
def solutions(list1):
        list2 = defaultdict(int)
        for elements in list1:

在开头加一个from collections import defaultdict

张仙东

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4,
         14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]


list2 = list(set(list1))
list2.sort()
arr = [[x, list1.count(x)] for x in list2]
print(arr)

libiao

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
max1 = max(list1)
min1 = min(list1)
a=[]
c=[]
for i in list1:
    b = list1.count(i)
    a.append(b)
for each in list1:
    if each not in c:
        c.append(each)
d = list(map(lambda x,y:[x,y],c,a))
d.sort()
print(d)

libiao

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
a=[]
c=[]
for i in list1:
    b = list1.count(i)
    a.append(b)
for each in list1:
    if each not in c:
        c.append(each)
d = list(map(lambda x,y:[x,y],c,a))
d.sort()
print(d)