Python：每日一题 133

冬雪雪冬

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题目：
已有一个列表如下
list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
由此生成新的列表，要求为一个2维列表，包括list1的每个不重复元素和在list1中出现的次数。例如12在list1中出现11次，就记为[12, 11]，最后按元素由小到大排序，生成如下的列表
[[0, 7], [1, 6], [2, 4], [3, 5], [4, 8], [5, 2], [6, 4], [7, 3], [8, 2], [9, 4], [10, 5], [11, 3], [12, 11], [13, 4], [14, 3], [15, 3], [16, 8], [17, 3], [18, 11], [19, 3], [20, 1]]

jerryxjr1220

print(sorted([[i, list1.count(i)] for i in set(list1)]))

千雪寒蝉

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4,
         16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8,
         18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16,
         14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
new_list = set(list1)
final_list = []
for i in new_list:
    num_group = [i,list1.count(i)]
    final_list.append(num_group)
print(final_list)

woduhaitao

# 查找列表中每个元素出现的次数
# list_original  原始列表
# list_target    目标输出
# list_temp      转换用列表，用于存放原始列表中不重复的元素
# list_cell      转换用列表，用于存放原始列表中出现的元素和次数
list_original = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18,
                17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10,
                2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18,
                4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1,
                9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17,5, 1, 13, 0, 10,
                0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
list_target = []
list_temp = []
list_cell = []
#将原始列表从小到大排序
list_original.sort()
#将元素列表中不重复的元素找出来，存放起来
for i in list_original:     
    if i not in list_temp:
        list_temp.append(i)
#print(list_temp)
#循环查找每个元素出现的次数        
for i in list_temp:
    list_cell =[i,list_original.count(i)]
    #将查找结果存放到列表中
    list_target.append(list_cell)
print(list_target)

冰封雪舞

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6,
         16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4,
         18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18,
         7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9,
         16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16,
         20, 18, 4, 18, 16, 3]
set1 = set(list1)
TT = []
for i in set1:
    d= list1.count(i)
    TT.append([i,d])
print(TT)

shigure_takimi

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
print([[i, list1.count(i)] for i in set(list1)])

# set好像是自动按从小到大排序的？

776667

def fun133(list_x):
    result = []
    for i in range(min(list_x),max(list_x)+1):
        result.append([i,list_x.count(i)])
    return result

if __name__ == '__main__':
    print(fun133([12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]))

浪子无名1517

set1 = set(list1)
    list2 = []
    for i in  set1:
        list2 .append([i, list1.count(i)])
    print(list2)

小黑大人

list1 = [12,1,3,19,0,1,16,8,19,10,6,10,0,4,3,18,2,18,17,6,16,19,12,18,4,4,16,12,13,11,0,0,12,7,10,2,7,12,4,18,13,18,16,17,14,12,1,12,4,14,8,18,4,12,10,1,18,7,2,9,3,11,12,2,9,13,12,18,15,1,9,5,11,6,12,9,16,14,18,0,15,4,17,5,1,13,0,10,0,6,16,15,3,16,20,18,4,18,16,3]
list1.sort()
list2 = []
for i in range(max(list1)+1):
    n = list1.count(i)
    list2.append([i,n])
print(list2)

solomonxian

好像很久不见题目了，多写几个

from collections import Counter

def fun(lst):
    return sorted(Counter(lst).most_common())

def fun2(lst):
    counter = Counter(lst)
    return [[i, counter[i]] for i in counter]

def fun3(lst):
    return [[i, lst.count(i)] for i in set(lst)]

bush牛

from collections import Counter
print(sorted([[i,j] for i,j in Counter(list1).most_common()]))

wyp02033

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0,
         0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11,
         12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3,
         16, 20, 18, 4, 18, 16, 3]

list1.sort()

set1 = set(list1)
result = []
for each in set1:
    result.append([each, list1.count(each)])
print(result)

结果：[[0, 7], [1, 6], [2, 4], [3, 5], [4, 8], [5, 2], [6, 4], [7, 3], [8, 2], [9, 4], [10, 5], [11, 3], [12, 11], [13, 4], [14, 3], [15, 3], [16, 8], [17, 3], [18, 11], [19, 3], [20, 1]]

tuple小白

先排序列表 然后去重 在找出出现的位置

万事屋

用堆写的。。也不知道名称和写法正不正规

def dsort(ll):
    d=[[ll.pop(),1,-1,-1]]
    ld=1
    for i in ll:
        ss=0
        while 1:
            if d[ss][0]==i:
                d[ss][1]+=1
                break
            elif d[ss][0]>i:
                if d[ss][2]==-1:
                    d.append([i,1,-1,-1])
                    d[ss][2]=ld
                    ld+=1
                    break
                else:
                    ss=d[ss][2]
            elif d[ss][0]<i:
                if d[ss][3]==-1:
                    d.append([i,1,-1,-1])                   
                    d[ss][3]=ld
                    ld+=1
                    break
                else:
                    ss=d[ss][3]
    return d
def showlist(d,ss):
    if ss==-1:
        return []
    else:
        return showlist(d,d[ss][2])+[d[ss][0:2]]+showlist(d,d[ss][3])
    
ll=[12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
ff=dsort(ll)
ans=showlist(ff,0)
print(ans)

无郁

list2=[0,3,2,3,4,8,6,7,8,9,5,8,7,6,5,4,3,5,1,0,2,4,6,8,]
#创建集合，存放不重复数字
j=set()
#遍历list2
for x in list2:

    j.add(x)
#将集合转换成列表
list3=list(j)
#排序
list3.sort()
print (list2)
print(list3)
#创建列表5存放结果
list5=[]
#print (list4)
for y in list3:
    #统计数字出现的次数
    a=list2.count(y)
    #print (a)
    #创建新列表4存放数字和出现的次数
    list4 = []
    list4.append(y)
    list4.append(a)
    #将列表4添加到列表5中
    list5.append(list4)
print (list5)

aegis1417

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13,
         11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7,
         2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10,
         0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
answer=[]
list2=list(set(list1))
list2.sort()
for i in list2:
        answer.append([i,list1.count(i)])
print(answer)

timeislife

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6,16,
         19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10,2, 7, 12, 4, 18, 13,
         18, 16, 17, 14,12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3,
         11, 12, 2, 9, 13,12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14,18, 0, 15,
         4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18,16, 3]
temp = sorted(list(set(list1)))
returnedlist = [[each,list1.count(each)] for each in temp]
print(returnedlist)

321123

list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4, 16, 12, 13, 11, 0, 0, 12, 7, 10, 2, 7, 12, 4, 18, 13, 18, 16, 17, 14, 12, 1, 12, 4, 14, 8, 18, 4, 12, 10, 1, 18, 7, 2, 9, 3, 11, 12, 2, 9, 13, 12, 18, 15, 1, 9, 5, 11, 6, 12, 9, 16, 14, 18, 0, 15, 4, 17, 5, 1, 13, 0, 10, 0, 6, 16, 15, 3, 16, 20, 18, 4, 18, 16, 3]
>>> temp=[]
>>> for each in list1:
        temp.append(list1.count(each))

       
>>> list2=sorted(zip(list1,temp))
>>> print(list2)

321123

321123 发表于 2018-1-7 11:34
list1 = [12, 1, 3, 19, 0, 1, 16, 8, 19, 10, 6, 10, 0, 4, 3, 18, 2, 18, 17, 6, 16, 19, 12, 18, 4, 4,  ...

但是我的输出是[(0, 7), (0, 7), (0, 7), (0, 7), (0, 7), (0, 7), (0, 7), (1, 6), (1, 6), (1, 6), (1, 6), (1, 6), (1, 6), (2, 4), (2, 4), (2, 4), (2, 4), (3, 5), (3, 5), (3, 5), (3, 5), (3, 5), (4, 8), (4, 8), (4, 8), (4, 8), (4, 8), (4, 8), (4, 8), (4, 8), (5, 2), (5, 2), (6, 4), (6, 4), (6, 4), (6, 4), (7, 3), (7, 3), (7, 3), (8, 2), (8, 2), (9, 4), (9, 4), (9, 4), (9, 4), (10, 5), (10, 5), (10, 5), (10, 5), (10, 5), (11, 3), (11, 3), (11, 3), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (12, 11), (13, 4), (13, 4), (13, 4), (13, 4), (14, 3), (14, 3), (14, 3), (15, 3), (15, 3), (15, 3), (16, 8), (16, 8), (16, 8), (16, 8), (16, 8), (16, 8), (16, 8), (16, 8), (17, 3), (17, 3), (17, 3), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (18, 11), (19, 3), (19, 3), (19, 3), (20, 1)] 怎么解决能让他只出现一次

321123

temp=[]
>>> for each in list1:
        temp.append(list1.count(each))

        
>>> list2=sorted(zip(list1,temp))
>>> list3=[]
>>> for each in list2:
        if each not in list3:
                list3.append(each)

               
>>> list3