Seawolf 发表于 2019-9-10 04:13:09

leetcode 237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list -- head = , which looks like following:



Example 1:

Input: head = , node = 5
Output:
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:

Input: head = , node = 1
Output:
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.


Note:

The linked list will have at least two elements.
All of the nodes' values will be unique.
The given node will not be the tail and it will always be a valid node of the linked list.
Do not return anything from your function.


/**
* Definition for singly-linked list.
* public class ListNode {
*   int val;
*   ListNode next;
*   ListNode(int x) { val = x; }
* }
*/
class Solution {
    public void deleteNode(ListNode node) {
      
                     
      node.val = node.next.val;

      if(node.next.next != null){

            node.next = node.next.next;
            node = node.next;
      }

      else
            node.next = null;
            
      

    }
      
   
}
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