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[学习笔记] leetcode 237. Delete Node in a Linked List

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发表于 2019-9-10 04:13:09 | 显示全部楼层 |阅读模式

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  1. Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

  2. Given linked list -- head = [4,5,1,9], which looks like following:

  3. 1.jpg

  4. Example 1:

  5. Input: head = [4,5,1,9], node = 5
  6. Output: [4,1,9]
  7. Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
  8. Example 2:

  9. Input: head = [4,5,1,9], node = 1
  10. Output: [4,5,9]
  11. Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.


  12. Note:

  13. The linked list will have at least two elements.
  14. All of the nodes' values will be unique.
  15. The given node will not be the tail and it will always be a valid node of the linked list.
  16. Do not return anything from your function.
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  1. /**
  2. * Definition for singly-linked list.
  3. * public class ListNode {
  4. *     int val;
  5. *     ListNode next;
  6. *     ListNode(int x) { val = x; }
  7. * }
  8. */
  9. class Solution {
  10.     public void deleteNode(ListNode node) {
  11.         
  12.                      
  13.         node.val = node.next.val;

  14.         if(node.next.next != null){

  15.             node.next = node.next.next;
  16.             node = node.next;
  17.         }

  18.         else
  19.             node.next = null;
  20.             
  21.         

  22.     }
  23.         
  24.    
  25. }
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