“int“迭代
list1=list2=
list3=
list4=
num=eval(input("请输入您的学号:"))
while num == (list1):
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum(list2+list3+list4))
break
while num == (list1):
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum(list2+list3+list4))
break
while num == (list1):
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum(list2+list3+list4))
break
while num == (list1):
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum(list2+list3+list4))
break
else:
print()
哪里出现了问题？？？
运行结果是这样的：
请输入您的学号:1
Traceback (most recent call last):
File "C:\Users\86198\AppData\Local\Programs\Python\Python37\p23.py", line 7, in <module>
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum(list2+list3+list4))
TypeError: 'int' object is not iterable
>>>
本帖最后由 jackz007 于 2020-11-13 22:18 编辑
list1=
list2=
list3=
list4=
num=eval(input("请输入您的学号:"))
if num == list1:
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum((list2 , list3 , list4)))
elif num == list1:
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum((list2 , list3 , list4)))
elif num == list1:
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum((list2 , list3 , list4)))
elif num == list1:
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",sum((list2 , list3 , list4)))
else:
print() jackz007 发表于 2020-11-13 22:13
想问一下为什么加了括号就不会出现错误了？
本帖最后由 jackz007 于 2020-11-13 22:31 编辑
嗨姐 发表于 2020-11-13 22:24
想问一下为什么加了括号就不会出现错误了？
不仅加了括号，而且，还把加号换成了逗号，这样写，sum() 的输入参数就是一个由三个元素组成的元组。
其实，如果按你的写法，直接用三个元素的和就可以了，没有必须再把这个和作为输入参数调用 sum() 函数。也就是说，直接把 sum() 去掉就可以了。
就像这样：
print("该学生成绩为语文",list2,",数学",list3,",英语",list4,",总分",list2+list3+list4) 谢谢！！
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