[已解决]“int“迭代

嗨姐

list1=[1,2,3,4]
list2=[98,67,89,80]
list3=[100,90,83,62]
list4=[90,98,100,82]
num=eval(input("请输入您的学号:"))
while num == (list1[0]):
    print("该学生成绩为语文",list2[0],",数学",list3[0],",英语",list4[0],",总分",sum(list2[0]+list3[0]+list4[0]))
    break
while num == (list1[1]):
    print("该学生成绩为语文",list2[1],",数学",list3[1],",英语",list4[1],",总分",sum(list2[1]+list3[1]+list4[1]))
    break
while num == (list1[2]):
    print("该学生成绩为语文",list2[2],",数学",list3[2],",英语",list4[2],",总分",sum(list2[2]+list3[2]+list4[2]))
    break
while num == (list1[3]):
    print("该学生成绩为语文",list2[3],",数学",list3[3],",英语",list4[3],",总分",sum(list2[3]+list3[3]+list4[3]))
    break
else:
    print()

哪里出现了问题？？？
运行结果是这样的：
请输入您的学号:1
Traceback (most recent call last):
  File "C:\Users\86198\AppData\Local\Programs\Python\Python37\p23.py", line 7, in <module>
    print("该学生成绩为语文",list2[0],",数学",list3[0],",英语",list4[0],",总分",sum(list2[0]+list3[0]+list4[0]))
TypeError: 'int' object is not iterable
>>>

最佳答案

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jackz007

2020-11-13 22:13:50

1. list1=[1,2,3,4]
   
2. list2=[98,67,89,80]
   
3. list3=[100,90,83,62]
   
4. list4=[90,98,100,82]
   
5. num=eval(input("请输入您的学号:"))
   
6. if num == list1[0]:
   
7.     print("该学生成绩为语文",list2[0],",数学",list3[0],",英语",list4[0],",总分",sum((list2[0] , list3[0] , list4[0])))
   
8. elif num == list1[1]:
   
9.     print("该学生成绩为语文",list2[1],",数学",list3[1],",英语",list4[1],",总分",sum((list2[1] , list3[1] , list4[1])))
   
10. elif num == list1[2]:
    
11.     print("该学生成绩为语文",list2[2],",数学",list3[2],",英语",list4[2],",总分",sum((list2[2] , list3[2] , list4[2])))
    
12. elif num == list1[3]:
    
13.     print("该学生成绩为语文",list2[3],",数学",list3[3],",英语",list4[3],",总分",sum((list2[3] , list3[3] , list4[3])))
    
14. else:
    
15.     print()

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jackz007

1. list1=[1,2,3,4]
   
2. list2=[98,67,89,80]
   
3. list3=[100,90,83,62]
   
4. list4=[90,98,100,82]
   
5. num=eval(input("请输入您的学号:"))
   
6. if num == list1[0]:
   
7.     print("该学生成绩为语文",list2[0],",数学",list3[0],",英语",list4[0],",总分",sum((list2[0] , list3[0] , list4[0])))
   
8. elif num == list1[1]:
   
9.     print("该学生成绩为语文",list2[1],",数学",list3[1],",英语",list4[1],",总分",sum((list2[1] , list3[1] , list4[1])))
   
10. elif num == list1[2]:
    
11.     print("该学生成绩为语文",list2[2],",数学",list3[2],",英语",list4[2],",总分",sum((list2[2] , list3[2] , list4[2])))
    
12. elif num == list1[3]:
    
13.     print("该学生成绩为语文",list2[3],",数学",list3[3],",英语",list4[3],",总分",sum((list2[3] , list3[3] , list4[3])))
    
14. else:
    
15.     print()

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嗨姐

jackz007 发表于 2020-11-13 22:13

想问一下为什么加了括号就不会出现错误了？

jackz007

嗨姐 发表于 2020-11-13 22:24
想问一下为什么加了括号就不会出现错误了？

     不仅加了括号，而且，还把加号换成了逗号，这样写，sum() 的输入参数就是一个由三个元素组成的元组。

     其实，如果按你的写法，直接用三个元素的和就可以了，没有必须再把这个和作为输入参数调用 sum() 函数。也就是说，直接把 sum() 去掉就可以了。

     就像这样：

1.     print("该学生成绩为语文",list2[0],",数学",list3[0],",英语",list4[0],",总分",list2[0]+list3[0]+list4[0])

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嗨姐

谢谢！！