Python列表自定义排序问题求助
题目：扑克牌有四种花色：黑红梅方。扑克牌按点数从小到大是2，3，4，……，J,Q,K,A。编程序实现下列目标：（1）按花色排序输出（小到大）
（2）按花色排序后，将同色牌按点数排序输出（大到小）
（3）第2步完成后，去除相同花色中数字重复的牌
下面是我的代码，感觉没什么问题，可就是运行之后毫无效果
importfunctools
Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
def custom_cmp1(x, y):
arr = ['黑桃','红桃','梅花','方块']
if arr.index(x) < arr.index(y):
return 1
else:
return -1
def StyleSort(*args):
new = list(args)
newlist = sorted(new,key=functools.cmp_to_key(custom_cmp1))
return newlist
def custom_cmp2(x, y):
arr = ['J','Q','K','A']
if x == y:
if arr.index(x) < arr.index(y):
return 1
else: return -1
def PointSort(*args):
newlist = sorted(args,key=functools.cmp_to_key(custom_cmp2))
return newlist
def DelRepeat(*args):
for i in range(len(args)):
for j in range(i+1,len(args)):
if args == args:
args = 'del'
tmplist =
newlist = list(tmplist)
return newlist
自己写了下，看看行不行达到需求：
from itertools import groupby
Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
arr = ['黑桃','红桃','梅花','方块']
num = {'J':11, 'Q':12, 'K':13, 'A':14}
Cards.sort(key=lambda x:arr.index(x[:2]))
New_Cards = groupby(Cards,lambda x:x[:2])
New_Cards =
result = []
for i in range(len(New_Cards)):
New_Cards.sort(key=lambda x: int(x) if x.isdigit() else num])
]
print(result) Twilight6 发表于 2021-7-16 20:33
自己写了下，看看行不行达到需求：
啊这，非常好，可是我看不懂{:10_282:} Dogelike 发表于 2021-7-17 13:19
啊这，非常好，可是我看不懂
代码中 [] 中括号中 for 循环就是列表推导式，第 13 行 lambad 匿名函数后面用的是 if -else 三目运算符
groupby 是分组函数，将同花色分组
Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
arr = ['黑桃','红桃','梅花','方块']
num = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
all_cards =
res = sorted(set(Cards), key=all_cards.index)
print(res)
页:
[1]