[已解决]Python列表自定义排序问题求助

Dogelike

题目：扑克牌有四种花色：黑红梅方。扑克牌按点数从小到大是2，3，4，……，J,Q,K,A。编程序实现下列目标：
（1）按花色排序输出（小到大）
（2）按花色排序后，将同色牌按点数排序输出（大到小）
（3）第2步完成后，去除相同花色中数字重复的牌
下面是我的代码，感觉没什么问题，可就是运行之后毫无效果
import  functools
Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
def custom_cmp1(x, y):
    arr = ['黑桃','红桃','梅花','方块']
    if arr.index(x[0:1]) < arr.index(y[0:1]):
        return 1
    else:
        return -1
def StyleSort(*args):
    new = list(args)
    newlist = sorted(new,key=functools.cmp_to_key(custom_cmp1))
    return newlist
def custom_cmp2(x, y):
    arr = ['J','Q','K','A']
    if x[0:1] == y[0:1]:
        if arr.index(x[2]) < arr.index(y[2]):
            return 1
        else: return -1
def PointSort(*args):
    newlist = sorted(args,key=functools.cmp_to_key(custom_cmp2))
    return newlist
def DelRepeat(*args):
    for i in range(len(args)):
        for j in range(i+1,len(args)):
            if args[i] == args[j]:
                args[j] = 'del'
    tmplist = [e for e in args if e != 'del']
    newlist = list(tmplist)
    return newlist

最佳答案

月排行榜 / 总排行榜

Twilight6

2021-7-16 20:33:57

自己写了下，看看行不行达到需求：

from itertools import groupby

Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
arr = ['黑桃','红桃','梅花','方块']
num = {'J':11, 'Q':12, 'K':13, 'A':14}

Cards.sort(key=lambda x:arr.index(x[:2]))
New_Cards = groupby(Cards,lambda x:x[:2])
New_Cards = [list(set(j)) for i,j in New_Cards]

result = []
for i in range(len(New_Cards)):
    New_Cards[i].sort(key=lambda x: int(x[2:]) if x[2:].isdigit() else num[x[2]])
    [result.append(j) for j in New_Cards[i]]

print(result)

跳转到最佳答案楼层

Twilight6

自己写了下，看看行不行达到需求：

from itertools import groupby

Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
arr = ['黑桃','红桃','梅花','方块']
num = {'J':11, 'Q':12, 'K':13, 'A':14}

Cards.sort(key=lambda x:arr.index(x[:2]))
New_Cards = groupby(Cards,lambda x:x[:2])
New_Cards = [list(set(j)) for i,j in New_Cards]

result = []
for i in range(len(New_Cards)):
    New_Cards[i].sort(key=lambda x: int(x[2:]) if x[2:].isdigit() else num[x[2]])
    [result.append(j) for j in New_Cards[i]]

print(result)

Dogelike

Twilight6 发表于 2021-7-16 20:33
自己写了下，看看行不行达到需求：

啊这，非常好，可是我看不懂

Twilight6

Dogelike 发表于 2021-7-17 13:19
啊这，非常好，可是我看不懂

代码中 [  ] 中括号中 for 循环就是列表推导式，第 13 行 lambad 匿名函数后面用的是 if -else 三目运算符

groupby 是分组函数，将同花色分组

qq1151985918

Cards = ['梅花A','方块4','梅花2','方块4','红桃7','黑桃Q','红桃K','梅花9','方块9','红桃5','梅花J','方块8','红桃5','黑桃3','黑桃10','黑桃3','红桃7','黑桃Q']
arr = ['黑桃','红桃','梅花','方块']
num = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
all_cards = [c + n for c in arr for n in num]
res = sorted(set(Cards), key=all_cards.index)
print(res)