python
steps = 7i = 1
FIND = False
while i < 100:
if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
FIND = True
else:
steps = 7 * (i + 1)
i = i + 1
if FIND == True:
print('阶梯数是：', steps)
else:
print('在程序限定的范围内找不到答案！')
这个是7的倍数问题我想显示在100倍数以内所有满足的数字和对应的7的倍数
这是爱因斯坦阶梯问题，参考代码：
steps = 7
i = 1
while i < 100:
if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
print('阶梯数是：', steps)
steps = 7 * (i + 1)
i = i + 1
还可以这样改：
steps = 7
print("阶梯数是：", end="")
while steps < 1000:
if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
print(steps, end=" ")
steps = steps + 7
steps = 7
i = 1
while i < 100:
if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
print(f'满足条件的数字：{i}，对应的7的倍数：{steps}')
else:
steps = 7 * (i + 1)
i = i + 1
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