[已解决]python

tengke

steps = 7
i = 1
FIND = False
while i < 100:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        FIND = True
    else:
        steps = 7 * (i + 1)
    i = i + 1
if FIND == True:
    print('阶梯数是：', steps)
else:
    print('在程序限定的范围内找不到答案！')
这个是7的倍数问题  我想显示在100倍数以内所有满足的数字和对应的7的倍数

最佳答案

月排行榜 / 总排行榜

Twilight6

2022-5-9 15:02:04

这是爱因斯坦阶梯问题，参考代码：

steps = 7
i = 1
while i < 100:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        print('阶梯数是：', steps)
    steps = 7 * (i + 1)
    i = i + 1

还可以这样改：

steps = 7
print("阶梯数是：", end="")
while steps < 1000:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        print(steps, end=" ")
    steps = steps + 7

跳转到最佳答案楼层

Twilight6

这是爱因斯坦阶梯问题，参考代码：

steps = 7
i = 1
while i < 100:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        print('阶梯数是：', steps)
    steps = 7 * (i + 1)
    i = i + 1

还可以这样改：

steps = 7
print("阶梯数是：", end="")
while steps < 1000:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        print(steps, end=" ")
    steps = steps + 7

isdkz

steps = 7
i = 1
while i < 100:
    if (steps % 2 == 1) and (steps % 3 == 2) and (steps % 5 == 4) and (steps % 6 == 5):
        print(f'满足条件的数字：{i}，对应的7的倍数：{steps}')
    else:
        steps = 7 * (i + 1)
    i = i + 1