论坛 › Python交流 › 代码敲出来跟想要的有出入，大佬看看该怎么改

爱意随风起9306 发表于 2022-12-30 15:11:11

代码敲出来跟想要的有出入，大佬看看该怎么改

N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      print("{} its factors are {}".format(num ,num_list))

代码输出的结果
6 its factors are
28 its factors are
496 its factors are



想要的结果
6 its factors are 1 2 3
28 its factors are 1 2 4 7 14
496 its factors are 1 2 4 8 16 31 62 124 248

isdkz 发表于 2022-12-30 15:17:51

N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      print("{} its factors are {}".format(num , ' '.join(num_list)))# 改了这里

柿子饼同学 发表于 2022-12-30 15:19:58

N = int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      print(num, "its factors are ", end = " ")
      for number in num_list:
            print(number, end = " ")
      print()

tommyyu 发表于 2022-12-30 15:21:05

isdkz 发表于 2022-12-30 15:17


这个貌似不行吧{:10_282:}>>> ' '.join()
Traceback (most recent call last):
File "<pyshell#7>", line 1, in <module>
    ' '.join()
TypeError: sequence item 0: expected str instance, int found

tommyyu 发表于 2022-12-30 15:23:42

N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      print("{} its factors are {}".format(num, str(num_list).replace(',', '')) )
或者N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      nums = ''
      for i in num_list: nums += str(i)+' '
      print("{} its factors are {}".format(num, nums[:len(nums)-1]))#去掉末尾空格

isdkz 发表于 2022-12-30 15:24:13

tommyyu 发表于 2022-12-30 15:21
这个貌似不行吧

是我疏忽了，我改一下

isdkz 发表于 2022-12-30 15:24:56

本帖最后由 isdkz 于 2022-12-30 15:33 编辑

N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
      if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
      print("{} its factors are {}".format(num , ' '.join(map(str, num_list))))# 改了这里

爱意随风起9306 发表于 2022-12-30 15:39:32

isdkz 发表于 2022-12-30 15:24


输入20224
输出最后一项的时候卡了。运行超时
20224
6 its factors are1 2 3
28 its factors are1 2 4 7 14
496 its factors are1 2 4 8 16 31 62 124 248
8128 its factors are1 2 4 8 16 32 64 127 254 508 1016 2032 4064

isdkz 发表于 2022-12-30 15:47:02

爱意随风起9306 发表于 2022-12-30 15:39
输入20224
输出最后一项的时候卡了。运行超时
20224


数太大了，建议改进一下算法

爱意随风起9306 发表于 2022-12-30 16:04:39

isdkz 发表于 2022-12-30 15:47
数太大了，建议改进一下算法

{:5_99:}

chinajz 发表于 2022-12-30 16:08:47

for num in range(2, N):
改成for num in range(2, N+1):
要不然执行不到N

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