[已解决]代码敲出来跟想要的有出入，大佬看看该怎么改

爱意随风起9306

N=int(input())
for num in range(2, N):
    num_list = []
    for i in range(1, num):
        if num % i == 0:
            num_list.append(i)
    if num == sum(num_list):
        print("{} its factors are {}".format(num ,num_list))

代码输出的结果
6 its factors are [1, 2, 3]
28 its factors are [1, 2, 4, 7, 14]
496 its factors are [1, 2, 4, 8, 16, 31, 62, 124, 248]



想要的结果
6 its factors are 1 2 3
28 its factors are 1 2 4 7 14
496 its factors are 1 2 4 8 16 31 62 124 248

最佳答案

月排行榜 / 总排行榜

isdkz

2022-12-30 15:24:56

1. N=int(input())
   
2. for num in range(2, N):
   
3.     num_list = []
   
4.     for i in range(1, num):
   
5.         if num % i == 0:
   
6.             num_list.append(i)
   
7.     if num == sum(num_list):
   
8.         print("{} its factors are {}".format(num , ' '.join(map(str, num_list))))  # 改了这里

复制代码

跳转到最佳答案楼层

isdkz

1. 
   
2. N=int(input())
   
3. for num in range(2, N):
   
4.     num_list = []
   
5.     for i in range(1, num):
   
6.         if num % i == 0:
   
7.             num_list.append(i)
   
8.     if num == sum(num_list):
   
9.         print("{} its factors are {}".format(num , ' '.join(num_list)))  # 改了这里

复制代码

柿子饼同学

1. N = int(input())
   
2. for num in range(2, N):
   
3.     num_list = []
   
4.     for i in range(1, num):
   
5.         if num % i == 0:
   
6.             num_list.append(i)
   
7.     if num == sum(num_list):
   
8.         print(num, "its factors are ", end = " ")
   
9.         for number in num_list:
   
10.             print(number, end = " ")
    
11.         print()

复制代码

tommyyu

isdkz 发表于 2022-12-30 15:17

这个貌似不行吧

1. >>> ' '.join([1, 2, 3])
   
2. Traceback (most recent call last):
   
3.   File "<pyshell#7>", line 1, in <module>
   
4.     ' '.join([1, 2, 3])
   
5. TypeError: sequence item 0: expected str instance, int found
   

复制代码

tommyyu

1. N=int(input())
   
2. for num in range(2, N):
   
3.     num_list = []
   
4.     for i in range(1, num):
   
5.         if num % i == 0:
   
6.             num_list.append(i)
   
7.     if num == sum(num_list):
   
8.         print("{} its factors are {}".format(num, str(num_list)[1:len(str(num_list))-1].replace(',', '')) )
   

复制代码

或者

1. N=int(input())
   
2. for num in range(2, N):
   
3.     num_list = []
   
4.     for i in range(1, num):
   
5.         if num % i == 0:
   
6.             num_list.append(i)
   
7.     if num == sum(num_list):
   
8.         nums = ''
   
9.         for i in num_list: nums += str(i)+' '
   
10.         print("{} its factors are {}".format(num, nums[:len(nums)-1]))#去掉末尾空格
    

复制代码

isdkz

tommyyu 发表于 2022-12-30 15:21
这个貌似不行吧

是我疏忽了，我改一下

isdkz

1. N=int(input())
   
2. for num in range(2, N):
   
3.     num_list = []
   
4.     for i in range(1, num):
   
5.         if num % i == 0:
   
6.             num_list.append(i)
   
7.     if num == sum(num_list):
   
8.         print("{} its factors are {}".format(num , ' '.join(map(str, num_list))))  # 改了这里

复制代码

爱意随风起9306

isdkz 发表于 2022-12-30 15:24

输入20224
输出最后一项的时候卡了。运行超时
20224
6 its factors are  1 2 3
28 its factors are  1 2 4 7 14
496 its factors are  1 2 4 8 16 31 62 124 248
8128 its factors are  1 2 4 8 16 32 64 127 254 508 1016 2032 4064

isdkz

爱意随风起9306 发表于 2022-12-30 15:39
输入20224
输出最后一项的时候卡了。运行超时
20224

数太大了，建议改进一下算法

爱意随风起9306

isdkz 发表于 2022-12-30 15:47
数太大了，建议改进一下算法

chinajz

for num in range(2, N):
改成for num in range(2, N+1):
要不然执行不到N