explain the utility of each function and their relations.
Explain the utility of each function in this program and their relation.
#include "stdafx.h"#include "stdio.h"struct fraction{ int numerator; int denominator;};struct fraction create(int, int);struct fraction add(struct fraction, struct fraction);struct fraction multiply(struct fraction, struct fraction);int _tmain(int argc, _TCHAR* argv[]){ struct fraction x,y, z; int m, n; printf("Numerator of fraction 1: "); scanf("%d",&m); printf("Denomintor of fraction 1: %d/", m); scanf("%d",&n); x = create(m, n); printf("Numeratorof fraction 2: "); scanf("%d",&m); printf("Denomintorof fraction 2: %d/", m); scanf("%d",&n); y = create(m, n); z = add(x, y); printf("%d/%d ＋ %d/%d =%d/%d\n", x.numerator,x.denominator, y.numerator,y.denominator, z.numerator,z.denominator); z = multiply(x, y); printf("%d/%d × %d/%d =%d/%d\n", x.numerator,x.denominator, y.numerator,y.denominator, z.numerator,z.denominator); return 0;}struct fraction create(int x, int y){ struct fraction f; f.numerator = x; f.denominator = y; return f;}struct fraction add(struct fraction x, struct fraction y){ int m, n, i; m = x.numerator *y.denominator + y.numerator * x.denominator; n = x.denominator *y.denominator; for (i = m; i >1; i--) if (n % i == 0&& m % i == 0) { m /= i; n /= i; } x.numerator = m; x.denominator = n; return x;}struct fraction multiply(struct fraction x, struct fractiony){ int m, n, i; m = x.numerator *y.numerator; n = x.denominator *y.denominator; for (i = m; i >1; i--) if (n % i == 0&& m % i == 0) { m /= i; n /= i; } x.numerator = m; x.denominator = n; return x;}
#include "stdafx.h"
#include "stdio.h"
struct fraction//自定义一个结构体
{
int numerator;//声明变量 分子
int denominator;//声明变量 分母
};
struct fraction create(int, int);
struct fraction add(struct fraction, struct fraction);
struct fraction multiply(struct fraction, struct fraction);
//声明三个结构体
int _tmain(int argc, _TCHAR* argv[])
{
struct fraction x,y,z;
int m, n;
printf("Numerator of fraction 1: ");
scanf("%d",&m);
printf("Denomintor of fraction 1: %d/", m);
scanf("%d",&n); //接收输入的两个数
x = create(m, n);//create函数是将输入的两个数付给结构体x.m、x.n
printf("Numeratorof fraction 2: ");
scanf("%d",&m);
printf("Denomintorof fraction 2: %d/", m);
scanf("%d",&n);
y = create(m, n);
z = add(x, y);
printf("%d/%d ＋ %d/%d =%d/%d\n",
x.numerator,x.denominator,
y.numerator,y.denominator,
z.numerator,z.denominator);
z = multiply(x, y);
printf("%d/%d × %d/%d =%d/%d\n",
x.numerator,x.denominator,
y.numerator,y.denominator,
z.numerator,z.denominator);
return 0;
}
struct fraction create(int x, int y)//定义结构体
{
struct fraction f;
f.numerator = x;
f.denominator = y;
return f;
}
struct fraction add(struct fraction x, struct fraction y)//定义结构体
{
int m, n, i;
m = x.numerator *y.denominator + y.numerator * x.denominator;
n = x.denominator *y.denominator;
for (i = m; i >1; i--)
if (n % i == 0&& m % i == 0)
{
m /= i;
n /= i;
}
x.numerator = m;
x.denominator = n;
return x;
}
struct fraction multiply(struct fraction x, struct fractiony)//定义结构体
{
int m, n, i;
m = x.numerator *y.numerator;
n = x.denominator *y.denominator;
for (i = m; i >1; i--)
if (n % i == 0&& m % i == 0)
{
m /= i;
n /= i;
}
x.numerator = m;
x.denominator = n;
return x;
}
函数具体实现的是什么你自己研究研究看看吧
页:
[1]