explain the utility of each function and their relations.

xsomonx

Explain the utility of each function in this program and their relation.

#include "stdafx.h"

#include "stdio.h"

struct fraction  

{

    int numerator;

    int denominator;

};

struct fraction create(int, int);

struct fraction add(struct fraction, struct fraction);

struct fraction multiply(struct fraction, struct fraction);

int _tmain(int argc, _TCHAR* argv[])

{

    struct fraction x,y, z;

    int m, n;

    printf("Numerator of fraction 1: ");

    scanf("%d",&m);

    printf("Denomintor of fraction 1: %d/", m);

    scanf("%d",&n);

    x = create(m, n);

    printf("Numeratorof fraction 2: ");

    scanf("%d",&m);

    printf("Denomintorof fraction 2: %d/", m);

    scanf("%d",&n);

    y = create(m, n);

    z = add(x, y);

    printf("%d/%d ＋ %d/%d =%d/%d\n",

        x.numerator,x.denominator,

        y.numerator,y.denominator,

        z.numerator,z.denominator);

    z = multiply(x, y);

    printf("%d/%d × %d/%d =%d/%d\n",

        x.numerator,x.denominator,

        y.numerator,y.denominator,

        z.numerator,z.denominator);

    return 0;

}

struct fraction create(int x, int y)

{

    struct fraction f;

    f.numerator = x;

    f.denominator = y;

    return f;

}

struct fraction add(struct fraction x, struct fraction y)

{

    int m, n, i;

    m = x.numerator *y.denominator + y.numerator * x.denominator;

    n = x.denominator *y.denominator;

    for (i = m; i >1; i--)

        if (n % i == 0&& m % i == 0)

        {

            m /= i;

            n /= i;

        }

    x.numerator = m;

    x.denominator = n;

    return x;

}

struct fraction multiply(struct fraction x, struct fractiony)

{

    int m, n, i;

    m = x.numerator *y.numerator;

    n = x.denominator *y.denominator;

    for (i = m; i >1; i--)

        if (n % i == 0&& m % i == 0)

        {

            m /= i;

            n /= i;

        }

    x.numerator = m;

    x.denominator = n;

    return x;

}  

maomingkun

#include "stdafx.h"
#include "stdio.h"
struct fraction  //自定义一个结构体
{
    int numerator;//声明变量 分子
    int denominator;//声明变量 分母
};
struct fraction create(int, int);
struct fraction add(struct fraction, struct fraction);
struct fraction multiply(struct fraction, struct fraction);
//声明三个结构体
int _tmain(int argc, _TCHAR* argv[])
{
    struct fraction x,y,z;
    int m, n;
    printf("Numerator of fraction 1: ");
    scanf("%d",&m);
    printf("Denomintor of fraction 1: %d/", m);
    scanf("%d",&n);     //接收输入的两个数
    x = create(m, n);//create函数是将输入的两个数付给结构体x.m、x.n
    printf("Numeratorof fraction 2: ");
    scanf("%d",&m);
    printf("Denomintorof fraction 2: %d/", m);
    scanf("%d",&n);
    y = create(m, n);
    z = add(x, y);
    printf("%d/%d ＋ %d/%d =%d/%d\n",
        x.numerator,x.denominator,
        y.numerator,y.denominator,
        z.numerator,z.denominator);
    z = multiply(x, y);
    printf("%d/%d × %d/%d =%d/%d\n",
        x.numerator,x.denominator,
        y.numerator,y.denominator,
        z.numerator,z.denominator);
    return 0;
}
struct fraction create(int x, int y)//定义结构体
{
    struct fraction f;
    f.numerator = x;
    f.denominator = y;
    return f;
}
struct fraction add(struct fraction x, struct fraction y)//定义结构体
{
    int m, n, i;
    m = x.numerator *y.denominator + y.numerator * x.denominator;
    n = x.denominator *y.denominator;
    for (i = m; i >1; i--)
        if (n % i == 0&& m % i == 0)
        {
            m /= i;
            n /= i;
        }
                x.numerator = m;
                x.denominator = n;
                return x;
}
struct fraction multiply(struct fraction x, struct fractiony)//定义结构体
{
    int m, n, i;
    m = x.numerator *y.numerator;
    n = x.denominator *y.denominator;
    for (i = m; i >1; i--)
        if (n % i == 0&& m % i == 0)
        {
            m /= i;
            n /= i;
        }
                x.numerator = m;
                x.denominator = n;
                return x;
}


函数具体实现的是什么你自己研究研究看看吧