S1E16：拾遗 | 课后测试题及答案,《带你学C带你飞》（语法篇）,C\C++交流,鱼C论坛

Lindaminmindear 发表于 2017-11-15 22:54:15

qq1724642151 发表于 2017-11-16 19:37:05

，，，，，，

brank 发表于 2017-11-16 20:53:45

打卡！

易天发表于 2017-11-16 21:11:59

看看

活力无极限1944 发表于 2017-11-18 20:25:14

本帖最后由活力无极限1944 于 2017-11-18 20:30 编辑

0，10个
1，0个
2，a b c
3，a=14，b=5，c=9
4， z = x >= 0 ? x : -x;
5，A
if (size > 12)
{
   cost = cost * 1.05;
   flag = 2;
}
bill = cost * flag;
B
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;
C
scanf("%d", &score);
while (score >= 0)
{
   count++;
   scanf("%d", &score);
}
printf("count = %d\n", count);
0，
#include <stdio.h>
#include <math.h>

int main()
{
float i, j;
int n;

for (n = 1; ;n++)
{
i = 10000 * 0.1 * n + 10000;
j = 10000 * pow(1 + 0.05 , n);

if (j > i)
{
break;
}
}

printf("%d年后，黑夜的投资额超过小甲鱼！\n", n);
printf("小甲鱼的投资额是：%.2f\n", i);
printf("黑夜的投资额是：%.2f\n", j);

return 0;
}
1，
#include <stdio.h>

int main()
{
int n;
float i;

for (n = 2, i = 350; ;n++)
{
i = i * (1 + 0.08) - 50;

if (i <= 0)
{
break;
}
}

printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗……\n", n);

return 0;
}

secrect 发表于 2017-11-19 03:36:14

1111

fang5888 发表于 2017-11-19 19:43:37

huifu

徐磊啊 发表于 2017-11-19 22:59:56

学习

批亢捣虚 发表于 2017-11-24 21:42:18

0. 100
1. 0
2. 5
3. a = 14; b = 5; c = 9
4. #include<stdio.h>

int main()
{
int i,z;

printf("请输入i的值：");
scanf("%d", &i);

if (i < 0)
{
z = -i;
}
else (z = i);
printf("%d", z);

return 0;
}
5.A: if (size > 12)
{
cost = cost * 12;
flag = 2;
}
else
{
bill = cost * flag;
}
B: if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;

0.

yaojiawang2016 发表于 2017-11-25 15:32:20

Vision 发表于 2017-11-27 14:24:07

本帖最后由 Vision 于 2017-11-27 14:33 编辑

动动手：

0.

#include <stdio.h>

int main()
{
int i=0;
double dl=0,fl=1,xjy=10000,hy=10000;

while(hy<=xjy)
{
dl=dl+10000.0*10/100;
xjy=10000+dl;
fl=fl*(1+0.05);
hy=10000*fl;
i++;
}

printf("%d年后，黑夜的投资额超过小甲鱼！\n",i);
printf("小甲鱼的投资额是：%.2lf\n",xjy);
printf("黑夜的投资额是：%.2lf\n",hy);

return 0;
}

--------------------------------------------

1.

#include <stdio.h>

int main()
{
double benjin=4000000;
int i=0;

while(benjin>=0)
{
benjin=(benjin-500000)*(1+0.08);
i++;
}

printf("%d年后，小甲鱼败光了所有的家产，再次回到一贫如洗...\n",i);

return 0;
}

----------------------------------------------------------------

2.

#include <stdio.h>
#include <math.h>

int main()
{
double pi=0;

{
int i=1,f=1;
double dx=1;

while(fabs(dx)>1e-8)
{
pi=pi+dx;
i=i+2;
f=-f;
dx=f*(double)1/i;
}
}
pi=pi*4;
printf("π ≈ %.7lf\n",pi);

return 0;
}

----------------------------------------------------------------

3.

#include <stdio.h>

int main()
{
int f1=1,f2=1,s,i;

for(i=3;i<=24;i++)
{
s=f1+f2;
f1=f2;
f2=s;
}

printf("两年后可以繁殖%d对兔子。\n",f2);

return 0;
}

风过无痕丶 发表于 2017-11-28 12:51:51

课后测试题及答案

太别致旳温柔 发表于 2017-11-28 14:40:20

0.10个
1.0个
2.a, b, c
3.a=3, b=5, c=9
4.z=(x > 0? x : -x)
5.
A:
if (size > 12)
{
cost = cost * 1.05;
flag =2;
}
else
{
bill = cost * flag;
}
B.
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
help = 2 * sheds;
}
C.
while (score >= 0)
{
count++;
scanf("%d", &score);
}
printf("count = %d\n", count);

太别致旳温柔 发表于 2017-11-28 14:47:36

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
float XiaoJiaYu, HeiYe;
float SingleInterest, CompoundInterest;
int countYear = 1;

SingleInterest = 0.1;
CompoundInterest = 0.05;
XiaoJiaYu = 10000 * (1 + SingleInterest);
HeiYe = 10000 *(1 + CompoundInterest);
while (XiaoJiaYu > HeiYe)
{
   countYear++;
   XiaoJiaYu += 10000 * SingleInterest;
   HeiYe *= (1 + CompoundInterest);
}
printf("%d年后，黑夜的投资超过小甲鱼！\n", countYear);
printf("小甲鱼的投资额是：%.2f\n", XiaoJiaYu);
printf("黑夜的投资额是：%.2f\n", HeiYe);

float XiaoJiaYu;
int Year = 1;

XiaoJiaYu = 3500000;
while (XiaoJiaYu > 0)
{
   Year++;
   XiaoJiaYu *= (1 + 0.08);
   XiaoJiaYu -= 500000;
}
printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗......", Year);

double i = 1.0, Denominator = 1.0;
double temp, sum = 1.0;

do
{
   i = -i;
   Denominator += 2;
   temp = i / Denominator;
   if (fabs(temp) > 0.00000001)
   {
         sum += temp;
   }
   else
   {
         break;
   }
} while (1);

sum *= 4.0;

printf("PI的近似值是：%.7f", sum);

int f1, f2, f3, sum;

f1 = f2 = 1;
sum = f1 + f2;
for (int i = 3; i <= 24; i++)
{

   f3 =f1 + f2;
   sum += f3;
   f1 = f2;
   f2 = f3;
}
printf("两年后总共繁殖了%d对兔子！\n", sum);
   return 0;
}

Zeon. 发表于 2017-11-28 20:00:38

great坏小孩 发表于 2017-11-28 20:22:18

核对答案

浅安丶 发表于 2017-11-29 14:21:52

0.10个
1.打印0个B。因为i=0;不执行循环。
2.cba
3.++c+++b左值错误。
4.z=(x>=0)?x:-x;
5.A:
if (size > 12)
{
   cost = cost * 1.05;
   flag = 2;
}
bill = cost * flag;

B:
if (ibex > 14)
{
   sheds = 3;
}
sheds = 2;
help = 2 * sheds;

C：
if (score < 0)
{
   gprintf("count = %d\n", count);
}
count++;
scanf("%d", &score);
动手0.
#include<stdio.h>

int main()
{
float a,b,y;
a=10000*0.1+10000;
b=10000*0.05+10000;
for(y=1;b<a;y++)
{
   a+=1000;
   b*=1.05;
}
printf("%0.0f年后，黑夜的投资额超过小甲鱼！\n",y);
printf("小甲鱼的投资额是：%0.2f\n",a);
printf("黑夜的投资额是：%0.2f",b);
return 0;
}
1.
#include<stdio.h>

int main()
{
float a,y;
a=3500000;
for(y=1;a>0;y++)
{
   a=a*1.08-500000;
}
printf("%0.0f年后，小甲鱼一贫如洗！\n",y);
return 0;
}
3.写的看起来有点蠢虽然结果是对了..

zjhnz 发表于 2017-11-29 22:54:34

xuexi

青春有悔！ 发表于 2017-12-3 09:54:24

对答案啊

ITsHtGN 发表于 2017-12-3 14:20:09

0.100
1.11
2.a, b, c
3.b = 5, c = 9

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