100;9;c;
int main()
{ float a=10000, b=10000, c=1;
int year;
for (year=1;a >= b;year++)
{
c = c * 1.05;
a = 1000 * year + 10000;
b = c * 10000;
}
printf("%d 年后,黑夜的投资超过小甲鱼。 \n",year);
printf("小甲鱼%f\n",a);
printf("黑夜%f\n",b);
return 0;
{:10_254:}
555
q
0
0. 0个
1. 10个
2.
3.a=14 ,b=5,c=9
4. (x=5?z:y);
5.
A
if (size > 12)
{
cost *= 1.05;
}
else
{
flag = 2;
bill *= flag;
}
B
略
C
略
0.
#include<stdio.h>
int main(void)
{
floatx, y;
int year = 1, i;
x = 10000.00;
y = 10000.00;
for (i = 1; 1 <= 100; i++)
{
x += (10000*0.1);
y += (y*0.05);
if (x > y)
{
year++;
continue;
}
else
{
printf("%d年后,黑夜的投资额超过小甲鱼!\n", year);
printf("小甲鱼是:%.2f\n", x);
printf("黑夜是:%.2f\n", y);
break;
}
}
return 0;
}
1.
略
2.
略
3.
略
6666
朕不想知道
。
1
测试题:
0.10个'A'
1.10个'B'
help = 2 * sheds;
2.a, b, c
3.b == 3
c = b++ + 5 == 9
a == ++c + ++b == 14
4.z = x >= 0 ? x : -x;
5.
A
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;
C
flag = socre < 0 ? 1 : 0;
if(flag == 1)
{
scanf("%d", score);
for ()
}
else if (flag == 0)
{
printf("count = %d\n", count);
}
kankan
爱迪达
看过来
l
{:10_323:}
1
{:5_91:}