b
学完这一课，准备停下来花一周时间消化好，再继续学
加油，努力
kj
1
是否得分
0.
10次
1.
0次
2.
a,b,c
3.
a=14,b=5,c=9
4.
x<0 ? z=x*-1 : z=x;
5.
①
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
②
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
help = 2 * sheds;
}
③
if (score < 0)
{
printf("count = %d\n", count);
}
else
{
count++;
scanf("%d", &score);
}
动动手
0.
#include<stdio.h>
int main()
{
int year;
double x,h;
for(year=0,x=10000, h=10000;h<=x;year++)
{
x = x+10000*0.1;
h = h+h*0.05;
}
printf("%d年后，黑夜的投资额超过小甲鱼！",year);
printf("小甲鱼:%f",x);
printf("黑夜:%f",h);
return 0;
}
1.
#include<stdio.h>
int main()
{
double m;
int year;
for(year=0,m=4000000;m>0;year++)
{
m = (m-500000) + (m-500000) * 0.08;
}
printf("%d",year);
return 0;
}
2.
#include<stdio.h>
int main()
{
double y,pi;
long long x;
for(y=1,x=3;fabs(1.0/x)>=1e-8;x+=4)
{
y=y-1.0/x+1.0/(x+2);
}
pi = y * 4;
printf("%.8f",pi);//精度定到7位的话最后一位会四舍五入，所以定到8位精度
return 0;
}
3.
不会做T T
1
让朕看看
dawda
{:5_109:}
1
10
0
5
14
4
10
1
ok
//
10
10
c
a = 5b =5 c =9
x > 0? x; -x;
if(size > 12){
cost = cost * 1.05;
flag = 2
}
bill = cost * flag;
if(ibex > 14){
sheds = 3;
}
sheds = 2;
help = 2 * sheds;
if(score < 0){
printf("count = %d\n", count);
}
count++;
scanf("%d", &score);
打卡
.
{:10_277:}