111
鱼C有你更精彩^_^
0：10个
1：0个
2：a=5
3:a=15、b=5、c=10
4: x = x<=0?x*-1:x;
5:
A:if (size > 12)
{
cost = cost * 1.05;
}
else{
bill = cost * flag;
}
B:if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;
C:while(count)
{
readin: scanf("%d", &score);
if (score < 0)
{
printf("count = %d\n", count);
}
count++;
}
发现评论区就我发截图{:10_259:}
1
17:04
学习打卡
支持
/*这是一个有趣的古典数学问题：如果说兔子在出生两个月后，就有繁殖能力，
在拥有繁殖能力之后，这对兔子每个月能生出一对小兔子来。
假设所有兔子都不会死去，能够一直干下去，那么两年之后可以繁殖多少对兔子呢？*/
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int gaici,i;
int sum;
int a=1;//当前兔子对数
int b=1;//当前可以繁殖的兔子对数
for(gaici=1,i=0;gaici<=24;gaici++,i++)
{
if (i%2==0&&i!=0)
{
b=b+1;
}
a=a+b;
printf("第%d月，共有%d对兔子，其中%d对兔子可以繁殖\n",gaici,a,b);
}
system("pause");
return 0;
}
1
那么
6
{:5_90:}
0. 10个
1.10
2.a
3.5610
4.#include<stdio.h>
int main()
{
int x;
scanf("%d",&x);
x>0? x = x:x = -1*x;
printf("%d\n",x);
return 0;
}
5.
Aif (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
Bif (ibex > 14)
{
sheds = 3;
}
sheds = 2;
else
{
help = 2 * sheds;
}
C
while(1)
{
if (score < 0)
{
printf("count = %d\n", count);
}
count++;
}
0.#include<stdio.h>
#include<math.h>
int main()
{
int xjy_money ;
int heiye_money;
int year = 1;
while(heiye_money<xjy_money)
{
xjy_money = 10000 + 1000*year;
heiye_money = 10000*pow(1.05,year);
year++;
}
printf("%d年后，黑夜的投资额超过小甲鱼！\n");
printf("小甲鱼的投资额是：%.2f\n",xjy_money);
printf("黑夜的投资额是：%.2f\n",heiye_money);
return 0;
}
1.#include<stdio.h>
int main()
{
float total_money = 400;
int year = 0;
while(total_money>=0)
{
total_money -=50;
total_money = total_money*1.08;
year++;
}
printf("%d",year);
return 0;
}
2.#include<stdio.h>
#include<math.h>
int main()
{
double pi = 0;
double i;
int count = 0;
for(i = 1;1/i>=0.00000001;i+=2)
{
int singal = pow(-1,count);
pi = pi + singal*(1/i);
count++;
}
pi = 4*pi;
printf("%.7f\n",pi);
return 0;
}
3.
。
测试题
0:100个A
1：1个B
2：a
3：a=11，b=3，c=8
4：if(x>0)
{
z=x;
}
else
{
z=-x;
}
5:
A:if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
B:if (ibex > 14) {
sheds = 3;
} else {
sheds = 2;
}
help = 2 * sheds;
C:readin: scanf("%d", &score);
if (score < 0)
{
printf("count = %d\n", count);
}
else
{
count++;
scanf("%d", &score);
}
动动手
0：
#include <stdio.h>
int main() {
float xiaojiafish = 10000;// 小甲鱼手上的钱
float heiye = 10000;// 黑夜手上的钱
float xiaojiafish_interest, heiye_interest = 0;// 利息
int year = 0;
while (xiaojiafish >= heiye) {
xiaojiafish_interest = xiaojiafish * 0.1;// 计算小甲鱼的单利息
xiaojiafish += xiaojiafish_interest;// 更新小甲鱼的总投资额
heiye_interest = heiye * 0.05;// 计算黑夜的复合利息
heiye += heiye_interest;// 更新黑夜的总投资额
year++;// 年数加一
}
printf("经过 %d 年，黑夜的投资额 %f 超过了小甲鱼的投资额 %f\n", year, heiye, xiaojiafish);
return 0;
}
1：
#include <stdio.h>
int main()
{
float a;
a = 400;
float b;
b = 0;
int year;
while(a >= 0)
{
b = a * 0.08;
a += b;
a = a - 50;
year++;
}
printf("经过 %d 年，小甲鱼败光属于家产，再次回到一贫如洗\n",year);
return 0;
}
2：
#include <stdio.h>
#include <math.h>
int main() {
double pi = 0.0;
double item = 1.0;
int i = 1;
while (fabs(item) >= 1e-8) {
pi += item;
i = -i;
item = 1.0 / (2 * i + 1);
}
pi *= 4;
printf("π 的近似值为: %.7f\n", pi);
return 0;
}
3：
#include <stdio.h>
#include <math.h>
int main() {
double pi = 0.0;
double item = 1.0;
int i = 1;
while (fabs(item) >= 1e-8) {
pi += item;
i = -i;
item = 1.0 / (2 * i + 1);
}
pi *= 4;
printf("π 的近似值为: %.7f\n", pi);
return 0;
}
22
朕想知道
本帖最后由 纪叶 于 2023-12-11 22:13 编辑
0. 10个
1.11个
2. a b c
3.a = 3，b = 4，c = 14，
4.z = x > 0 ?x : -x;
5.A
if (size > 12)
{cost = coast * 1.05;
break;
}
bill = cost *flag;
flag = 2;
B
if(ibex > 14)
{ sheds = 3;
break;
}
sheds = 2;
help = 2 * sheds;
C
if(score < 0)
{
printf("count = %d\n",count);
}
count++;
scanf("%d",&score);
0.
#include <stdio.h>
int main()
{
float fish = 10000.00, blacksky = 10000.00;
int year = 0;
while (blacksky <= fish)
{
fish = fish + 10000.00*0.1;
blacksky = blacksky *(1 + 0.05);
year++;
}
printf("%d年后，黑夜的投资额超过小甲鱼！\n",year);
printf("小甲鱼的投资额是：%.2f\n",fish);
printf("黑夜的投资额是：%.2f\n",blacksky);
return 0;
}
1.
#include <stdio.h>
int main()
{
float touzi = 400.00;
int year = 0;
while(touzi >= 0)
{
touzi = touzi - 50;
touzi += touzi*0.08;
year++;
}
printf("%d年后，小甲鱼败光了所有的家产，再次回到一贫如洗...",year);
return 0;
}
2.
朕想知道