S1E16：拾遗 | 课后测试题及答案,《带你学C带你飞》（语法篇）,C\C++交流,鱼C论坛

Sun-zY-Yang 发表于 2018-12-17 21:31:25

纵横天下3 发表于 2018-12-18 19:17:30

answer

Joyong 发表于 2018-12-20 15:45:40

1. 10
2. i = 11时，执行goto label ，然后退出。10次
3. a = 5, b = 5, c = 5
4. a = (b = 3, 4, c = 9 , 14)
5.if (size>12)
{
cost = cost * 1.o05;
flag = 2;
}
else
{
bill = cost * flag;
}

B if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help= 2 * sheds

轻鱼发表于 2018-12-20 22:38:07

1809228982 发表于 2018-12-22 10:57:14

哈哈

davidcq 发表于 2018-12-23 21:35:42

看看

我叫MD 发表于 2018-12-24 19:26:52

0.打印100次
1.打印10次
2.a = 5；
b = 5；
c = 5；
3.b == 5；c == 9； a = 14
4.z = x > 0 ? x : -x

sign 发表于 2018-12-25 14:50:28

0.10
1.0
2.a
3.a=14;b=5;c=9
4.if(-x > 0){z = x;}
else{z = x - 2x；}
5.A.if(size > 12){cost = 1 * 1.05;flag = 2；}
   else{bill = cost * flag;}
B.if(ibex > 14){sheds = 3;}
   else{sheds = 2;help = 2 * sheds;}
C.if(score < 0){printf("count = %d\n",count);
   else{count++;scanf("%d",&score);

mm为了你 发表于 2018-12-26 11:45:15

{:5_105:}

wyr190615 发表于 2018-12-26 13:57:51

111

resail 发表于 2018-12-27 18:05:52

0. 100次
1. 不打印
2. a b c
3. 14 5 9
4. z = x > 0?x : -x;
5.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;

if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;

if (score < 0)
{
printf("count = %d\n", count);
}
count++;
scanf("%d", &score);

0.
#include <stdio.h>

#define XJY 0.1
#define HY 0.05

int main()
{
int year = 0;
float xjy_money, hy_money;
xjy_money = hy_money = 10000;

do{
         year++;
   xjy_money += 10000 * XJY;
   hy_money = hy_money * (1 + HY);
}while (xjy_money >= hy_money);

printf("%d年后，黑夜的投资额超过小甲鱼！\n", year);
printf("小甲鱼的投资额是：%.2f\n", xjy_money);
printf("黑夜的投资额是：%.2f\n", hy_money);
return 0;
}

1.
#include <stdio.h>

#define LI 1.08
#define QU 50.0

int main()
{
float surplus = 400.0;
int year = 0;

do{
   year++;
   surplus -= QU;
   surplus *= LI;
}while (surplus >= 50);

printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗……\n", year + 1);
return 0;
}

2.
#include <math.h>

int main()
{
double Pi = 0, i = 1;
while (fabs(1 / i) > pow((double)10, -8)){
   Pi += 1 / i;
   i = i < 0? -i + 2 : -(i + 2);
}
printf("%.7f\n", Pi);
return 0;
}

3.
#include <stdio.h>

int main()
{
long sum = 0, i = 1, j = 2, temp;
int time = 3;
for (; time <= 24; time++){
   sum = i + j;
   temp = j;
   j = sum;
   i = temp;
}

printf("震惊！2年后有%ld对兔子！\n", sum);
return 0;
}

金光上人 发表于 2018-12-28 10:26:30

YanzzZ 发表于 2018-12-28 14:41:55

PLGR146 发表于 2018-12-29 22:32:40

0.100
1.11
2.a b c
3.14
4.x>0 ? z = x; z = -x;
5.A. if (size > 12)
{
cost = cost * 1.05;
flag = 2;
   bill = cost * flag;
}
bill = cost * flag;
B: if (ibex > 14)
{
sheds = 3;
help = 2 * sheds;
}
else
{
shed = 2;
help = 2 * sheds;
}
C: scanf("%d", &score);
while (score < 0)
{
if (score < 0)
{
printf("count = %d\n", count);
}
else
{
count++
}

0.
#include <stdio.h>
#define mian main
int mian()
{
double xjy;
double hyt;
double xjyt;
int year = 0;

for (xjyt = hyt = xjy = 10000; hyt <= xjyt; year++)
{
   xjyt = xjyt + xjy * 0.1;
   hyt = hyt + hyt * 0.05;
}

printf("%d年后，黑夜的投资额超过小甲鱼！\n小甲鱼的投资额是：%.2f\n黑夜的投资额是：%.2f\n", year, xjyt, hyt);
return 0;
}
1.#include <stdio.h>
#include <math.h>
#define mian main
int mian()
{
double xjy = 400;
int year = 0;

for (xjy = 400; xjy > 0; year++)
{
xjy = xjy - 50 + (xjy - 50) * 0.08;
}

printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗...\n", year);

system("pause");
return 0;
}

2.#include <stdio.h>
#include <math.h>
#define mian main
int mian()
{
double pi = 0;
double j = 1;
double i;

for (i = 1; fabs(1 / i) > pow(10, -8);)
{
pi = pi + 1 / i;
i = (i > 0) ? -(i + 2) : -i + 2;
//printf("%.10f %f\n", pi, i);
}

pi = 4 * pi;
printf("%.7f\n", pi);

system("pause");
return 0;
}

3.#include <stdio.h>
#include <math.h>
#define mian main
int mian()
{
int tz = 1;

for (int mt = 1; mt <= 24; mt++)
{
tz = tz * 2;
}

printf("假设所有兔子都不会死去，能够一直干下去，两年之后可以繁殖%d只兔子\n", tz);

system("pause");
return 0;
}

蓝漠花海 发表于 2018-12-29 22:57:01

π....求不出来

俞瑾迦 发表于 2018-12-30 16:08:30

emmmmmmmm

ahr123 发表于 2018-12-30 20:55:17

huangxiaohuang 发表于 2019-1-2 13:14:20

0 9个或者0个，在第一层循环中循环条件是j!=10，但是没有对j初始化，如果碰巧j就是10，那就是0次，否则进入第二层循环，循环十次并且循环结束j=10.

1 0个
2 c b a
3 a14 b5 c9
4 z = x >= 0 ? x : -x

5
A:
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}

bill = cost * flag;

B:
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}

help = 2 * sheds;

C:
while(1)
{
scanf("%d", &score);
if(score < 0)
{
printf("count = %d\n", count);
break;
}
count++;
}

#include <stdio.h>
#include <stdio.h>

int main()
{
double money = 1000, moneyJ, moneyH;
int year = 1;
float p1 = 10.0 / 100, p2 = 1 + 5.0 / 100;
for (year; ; year++)
{
   moneyJ = money + money * p1 * year;
   moneyH = money * pow(p2, year);

   if(moneyJ >= moneyH)
   {
         continue;
   }
   break;
}

printf("%d年后，黑夜的投资额超过小甲鱼！\n", year);
printf("小甲鱼的投资额是：%.2f\n", moneyJ);
printf("黑夜的投资额是：%.2f\n", moneyH);

return 0;
}

#include <stdio.h>

int main()
{
double money = 4000000, cost = 500000, p = 8.0 / 100;
int year = 0;

while(money > 0)
{
   money -= cost;
   money *= (1 + p);
   year++;

}

printf("%d年后，小甲鱼败光了所有的家产，再次变得一贫如洗......\n", year);

return 0;
}

#include <stdio.h>
#include <stdio.h>

int main()
{
double pi = 0.0, i;
int n = 1;
do
{
   i = pow (-1, (n-1)) / (2 * n - 1);
   pi = pi + i * 4;
   n++;

} while (fabs(i) >= pow(10, -8));

printf("Pi精确到小数点后七位的近似值是：%.7lf\n", pi);
}

dddzy 发表于 2019-1-4 00:10:56

SNADO 发表于 2019-1-4 21:34:17

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