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0. 请问下边代码将打印多少个 'A'？l{XbOt2r
RA39"X6IE}v_H`:SuNr%#=^fCw.0
1. #include <stdio.h>
2.
3. int main()
4. {
5. int i, j;
6.
7. for (i = 0; i != 10, j != 10; i++)
8. {
9. for (j = 0; j < 10; j++)
10. {
11. putchar('A');
12. }
13. }
14.
15. putchar('\n');
16.
17. return 0;
18. }
答：10个
1. 请问下边代码会打印多少个 'B'？0L:?F
]d|ojcH'5iq^2}W=K>7<B8y;wDfkPn
1. #include <stdio.h>
2.
3. int main()
4. {
5. int i = 0;
6.
7. while (i++)
8. {
9. if (i > 10)
10. {
11. goto Label;
12. }
13. putchar('B');
14. }
15.
16. Label:putchar('\n');
17.
18. return 0;
19. }
答：九个。
2. 请写出表达式 a = b = c = 5 中的"l-value"？
答：5
3. 请问表达式 a = (b = 3, 4, c = b++ + 5, ++c + ++b); 执行后，整型变量 a、b、c 的值是？
答：
A=13
B=5
C=9
4. 请使用条件运算符求出变量 x 的绝对值，并存放到变量 z 中。
答：
X>0?x:-x;
5. C 语言其实在大部分情况下不使用 goto 语句也能做得很好，请尝试将下列代码段写成不带 goto 语句的版本。u6BwLkd
"6Oo|nq>a=He1w~+B%@ 'pc&5C
A. 版权属于：bbs.fishc.com
1. if (size > 12)
2. {
3. goto a;
4. }
5. goto b;
6. a: cost = cost * 1.05;
7. flag = 2;
8. b: bill = cost * flag;
复制代码
If(size>12)
{
cost=cost*1.05;
}
Else
{
bill = cost*flag;
}
B. 版权属于：bbs.fishc.com
1. if (ibex > 14)
2. {
3. goto a;
4. }
5. sheds = 2;
6. goto b;
7. a: sheds = 3;
8. b: help = 2 * sheds;
复制代码
If(ibex>14)
{
sheds=3;
}
Else
{
Sheds-2;
Help=2*sheds;
}
C.版权属于：bbs.fishc.com
1. readin: scanf("%d", &score);
2. if (score < 0)
3. {
4. goto stage2;
5. }
6. count++;
7. goto readin;
8. stage2: printf("count = %d\n", count);
for(score=scanf(“%d”,&score);score>=0;count++)
{
score = scanf(“%d”,&score);
}
Printf(“count = %d\n”,count);
#include <stdio.h>
main()
{
float fish=10000.00,heiye=10000.0;
int year=0;
for (;fish>=heiye;year++)
{
fish += 1000;
heiye *=1.05;
}
printf("%d年后，黑夜的投资额超过小甲鱼！\n",year);
printf("小甲鱼的投资额是：%.2f\n",fish);
printf("黑夜的投资额是：%.2f\n",heiye);
}
#include <stdio.h>
main()
{
int year=0;
float money=400.00;
for (;;year++)
{
money -= 50;
if(money<0)
{
year++;
break;
}
else
{
money *=1.08;
}
}
printf("%d年之后，小甲鱼败光了所有的家产，再次回到一贫如洗......\n",year);
}
#include <stdio.h>
main()
{
long int sum,adult=1,child=0,new0=0,new1=0,newj=0;
int time;
for (time=0;time<=24;time++)
{
child=child+adult;
new0 = new1;
new2 = newj;
newj = adult;
adult +=new0;
}
sum = child+adult;
printf("一共有%ld对兔子！\n",sum);
}
~
答案
查看答案
ok
欧克
0.100次
1.0次
2.abc
3.16 6 10
4.z=(x>0)?x:-x;
5.A.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B.
if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;
C.
if (score < 0)
{
printf("count = %d\n", count);
}
count++;
scanf("%d", &score);
动动手0
#include <stdio.h>
#include <math.h>
int main(void) {
double money=10000,n1=0.1,n2=0.05,sum1,sum2;
for(int i=1;i<100;i++){
sum1=money+(money*n1*i);
sum2=money*pow((1+n2),i);
if(sum2>sum1){
printf("%d年后，黑夜投资额超过小甲鱼\n",i);
break;
}
}
printf("小甲鱼的投资额是:%.2lf\n",sum1);
printf("黑夜的投资额是:%.2lf\n",sum2);
return 0;
}
动动手1
#include <stdio.h>
#include <math.h>
int main(void) {
int sum=400,year;
double r=0.08;
for(year=1;year<100;year++){
sum=(sum-50)*(1+0.08);
if (sum<0){
printf("%d年后，败光！\n",year);
break;
}
}
return 0;
}
兔子好难{:10_247:}
0-9 10个
i++ 是0 不进入循环啊。。
a, a=b, a=b=c
b = 5 , c = 9
a = 9 + 5 = 14
z = x > 0 ? x:-x
if (size > 12)
{
cost = cost * 1.05;
}
flag = 2;
bill = cost * flag;
if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
help = 2 * sheds;
if (score < 0)
{
printf("count = %d\n", count);
}
count++;
scanf("%d", &score);
0.10个A
1.11
2.
3.8,3,3
4.
5.
1
: )
查看参考答案
看看
0. 10
1. 10
2.a,b, c
3. a = 12, b = 4, c = 8
4. z = |x|
5. if (size > 12)
{
cost = cost * 1.05;
}
else if(flag = 2)
{
bill = cost * flag;
}
2.
if (ibex > 14)
{
sheds = 3;
}
else if(sheds = 2;)
}
help = 2 * sheds;
}
3.
readin:scanf("%d", &score);
while(readin : scanf("%d", &scaore) == 0)
{
if(score < 0)
{
printf("count = %d\n", count);
}
}
{:10_266:}
无条件支持楼主！
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