Python：每日一题 1,Python交流,编程语言专区,鱼C论坛

pingws928 发表于 2017-8-16 20:01:34

list=[]
for i in range(1,5):
for j in range(1,5):
   if j==i:
         continue
   for k in range(1,5):
         if k == j or k == i:
            continue
         else:
            a=100*i+10*j+k
            list.append(a)
print('组合数:',len(list))

木一发表于 2017-8-19 21:24:05

list1 = []
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if i != j and j != k and k != i:
list1.append(i * 100 + j * 10 + k)
print('共有%d个！'% len(list1))
print('分别是：',end = '')
for each in list1:
print(each,end = ' ')
{:10_277:}

gausser 发表于 2017-9-4 00:17:41

count = 0
print "The number is: "
for i in range(1, 5):
for j in range(1, 5):
   for k in range(1, 5):
         if (i != j) and (j != k) and (i != k):
            count += 1
            print i * 100 + j * 10 + k,
            if count % 4 == 0:
               print
print "The count of number is:", count

Jocks 发表于 2017-9-5 21:48:45

本帖最后由 Jocks 于 2017-9-5 22:00 编辑

count = 0
for num1 in range(1,5):
for num2 in range(1,5):
   for num3 in range(1,5):
         if num1 != num2 and num1 != num3 and num2 != num3:
            print('%d%d%d'%(num1,num2,num3))
            count += 1
print('总共有%d个数符合条件' % count)

BngThea 发表于 2017-9-11 10:07:00

def countshow(list0 = ):

count = 0
listf = []
for h in list0:
   list0.remove(h)
   list1 = list0.copy()
   list0.append(h)
   for d in list1:
         list1.remove(d)
         list2 = list1.copy()
         list1.append(d)
         for u in list2:
            count += 1
            listf.append(100 * h + 10 * d + u)

print('满足条件的共有：' + str(count) + '个')
print(listf,end = ' ')

listt =
countshow(listt)

鸿鹄之志1993 发表于 2017-9-12 09:46:20

>>> tuple1 = (1, 2, 3, 4)
>>> tuple1
(1, 2, 3, 4)
>>> for each1 in tuple1:
for each2 in tuple1:
for each3 in tuple1:
print(each1, each2, each3)

张大象 发表于 2017-9-13 14:29:10

for i in range(1,5):
for j in range(1,5):
   for k in range(1,5):
         if i!=j and j!=k and i!=k:
            print(i,j,k,sep='',end=' ')

princessjudy 发表于 2017-9-13 16:48:14

plan A
list1 =
list2 = []
for aa in list1:
for bb in list1:
   if bb == aa:
         continue
   for cc in list1:
         if cc == bb or cc == aa:
            continue
         list2.append(int(str(aa) + str(bb) + str(cc)))

print(len(list2))
print()
print(list2)

plan B

list1 = []
list2 = []
for i in range(1,5):
for y in range(1,5):
   for x in range(1,5):
         list1.append(int(str(1) + str(y) + str(x)))

for aa in list1:
bb = list(str(aa))
if len(bb) == len(set(bb)):
   list2.append(aa)

print('总共有%d个不同的数字，他们分别是：' % len(list2))
for ss in list2:
print(ss)

懒惰有只猫 发表于 2017-9-13 17:13:03

本帖最后由懒惰有只猫于 2017-9-13 17:16 编辑

numbers = ['1','2','3','4']
results = []
for i in numbers:
for j in numbers:
   for k in numbers:
         if (i + j + k) not in results and i != j and j != k and i != k:
            results.append(i + j + k)

for result in results:
print (result)
print ('-------------')
print (len(results))

易水寒楠 发表于 2017-9-14 23:57:07

#-*-coding:gbk-*-
__author__ = 'chennan'
def count(w,x,y,z):
list1=
list2=[]
n3=0
while n3<=3:
   a=list1
   n3+=1
   n2=0
   while n2<=3:
      b=list1
      n2+=1
      n1=0
      while n1<=3:
            c=list1
            n1+=1
            d=a*100+b*10+c
            list2.append(d)
returnlist2;

2740710202 发表于 2017-9-21 13:49:53

for i in range(1,5):
for j in range(1,5):
   for k in range(1,5):
         if i !=j and j!=k and i!=k:
            print(i,j,k)

一题一题做

驻火蚁 发表于 2017-9-23 21:38:27

q=0
for i in range(1,5):
for j in range(1,5):
   for k in range(1,5):
         if i!=j and i!=k and j!=k:
            q+=1
            print(i,j,k,q)

aixuexi82 发表于 2017-9-25 14:38:50

for a in range(1,5):
for b in range(1,5):
   for c in range(1,5):
            if a != b != c:
               print(a*100+b*10+c)

Liuyl 发表于 2017-9-26 16:46:22

for下for就行啊，从个十百位排序来

口可口可 发表于 2017-10-8 19:50:32

本帖最后由口可口可于 2017-10-8 19:59 编辑

list=[]
for x in range(1,5):
for y in range(1,5):
   if y!=x:
         for z in range(1,5):
            if z!=x and z!=y:
               list.append(x * 100 + y * 10 + z)
print('符合条件的数字共有%d个'%len(list))
print('它们分别是：',end='')
for each in list:
print(each,end=' ')

符合条件的数字共有24个
它们分别是：123 124 132 134 142 143 213 214 231 234 241 243 312 314 321 324 341 342 412 413 421 423 431 432

Wikeys 发表于 2017-10-11 22:44:55

大佬们好，初学者
#-*-conding:UTF-8 -*-
for a in range(1,5):
for b in range(1,5):
for c in range(1,5):
if a != b and b != c and a != c:
print str(a)+str(b)+str(c)

zata 发表于 2017-10-13 16:37:17

新手上路！！！
temp = []
for i in range(1,5):
for j in range(1,5):
   for k in range(1,5):
         if i != j != k:
            temp.extend([(i,j,k)])
print(temp)

ytbihpl2017 发表于 2017-10-14 13:01:39

n = 0
for x in range(1,5):
for y in range(1,5):
      for z in range(1,5):
      if x != y andx != z and y != z:
            n+=1
            print(x,y,z)
print('一共有%d个数' % n)

顺德热心市民 发表于 2017-10-24 10:20:44

初学python先用以前学过的一点点java写写

class Untitled {
public static void main(String[] args) {
int i=0;
for(int a=1;a<=4;a++){
for(int b=1;b<=4;b++){
for(int c=1;c<=4;c++){
for(int d=1;d<=4;d++){
if(a!=b && a!=c && a!=d && b!=c && b!=d && c!=d){
System.out.println(1000*a+100*b+10*c+d);
i++;}
}
}
}
}
System.out.println("一共有 "+i+" 个数");
}
}

a778450868 发表于 2017-10-25 20:44:03

疑问,楼主看到回复下
代码if i != k and i != j and j != k: 这里只要两个就好了吧
i !=j and j !=k

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