我也来凑个数
count = 0
for i in range(1, 5):
for j in range(1, 5):
for k in range(1, 5):
if i != j and j != k and k != i:
count +=1
print(i, j, k)
print(count)
分别输出了各种可能和总和
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if i != k and i != j and j != k:
print(i,j,k)
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if i!=j and j!=k and k!=i:
print(i,j,k)
count=0
for i in range(1,5):
for j in range(1,5):
for z in range(1,5):
if i!=j and j!=z and i!=z:
print(i,j,z)
count+=1
print('一共有',count,'个')
for a in range(1,5):
for b in range(1,5):
for c in range(1,5):
if a!=b!=c:
print(a,b,c)
list = []
for i in range(1, 5):
for j in range(1, 5):
for k in range(1, 5):
if len({i, j, k}) == 3:
num = 100 * i + 10 * j + k
list.append(num)
print(list)
print(len(list))
print('一共有%d个数字' % (len(list)))
cinmay 发表于 2018-1-18 04:23
for a in range(1,5):
for b in range(1,5):
for c in range(1,5):
if a!=b!=c:
这个写法,似乎没有把a=c的排除掉喔...
我也来试试～
count=0
for x in range(1,5):
for y in range(1,5):
for z in range(1,5):
if x!=y!=z!=x :
print("{}{}{}".format(x,y,z),end=',')
count+=1
print("Total counts:",count)
123,124,132,134,142,143,213,214,231,234,241,243,312,314,321,324,341,342,412,413,421,423,431,432,Total counts: 24
#2018.01.24
#题目：有四个数字：1、2、3、4，能组成多少个互不相同且无重复数字的三位数？各是多少？
list1=[]
for i in range(1,5):
for j in range(1,5):
for n in range(1,5):
num=i*100+j*10+n
list1.append(num)
print(list1)
list2=[]
for m in list1:
p=str(m)
if(p==p or p==p or p==p):
list2.append(m)
list3=list(set(list1)-set(list2))
print(len(list3),list3)
1141429506 发表于 2018-1-24 19:26
#2018.01.24
#题目：有四个数字：1、2、3、4，能组成多少个互不相同且无重复数字的三位数？各是多少？
li ...
#简洁版
list4=[]
n = 0
for x in range(1, 5):
for y in range(1, 5):
for z in range(1, 5):
if (x != y and x != z and y != z):
n += 1
list4.append(x*100+y*10+z)
print(n,list4)
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if i !=k and i !=j and i !=k:
print(i,j,k)
list=[]
for i in range(1,5):
for j in range(1,5):
for k in range(1,5):
if i!=j and j!=k and i!=k:
a=100*i+10*j+k
list.append(a)
print('答案列表是:',list)
print('列表中元素总有:',len(list),'个')
用了评论中的一种方法练习{:10_254:}
for i in range(1,5):
for j in range(1,5):
for p in range(1,5):
for q in range(1,5):
if i!=j and j!=p and p!=q and j!=q and i!=p and i!=q:
print(i*1000+j*100+p*10+q)
现在还是只能看简单的，太难的看不懂
total = 0
for x in range(1,5):
for y in range(1,5):
for z in range(1,5):
if x != y and x != z and y != z:
print(x,y,z)
total += 1
print('共有%d个排序' % (total))
本帖最后由 若闲 于 2018-2-2 15:25 编辑
#排列组合1234
a =
b = []
for x in a:
for y in a:
for z in a:
b.append(x*100+y*10+z)
b = list(set(b))
print(len(b))
print(b)
互不相同且无重复数字的三位数
我就说你们怎么都这么写的……这里是有歧义的好吗？无重复数字到底是指这些三位数没有重复还是三位数里的每一位都互相不重复？{:10_266:}
#要的是三位数，应该要的是数字而不是str吧
m = 1,2,3,4
shuzi=[]
for i in m:
for s in m:
for g in m:
if i!=s and s != g and i != g:
I = int(i)*100 +int(s)* 10+int(g)
shuzi.append(I)
print(shuzi)
print"共有",len(shuzi),"个数字"
count = 0
grade = []
for x in range(1,5):
for y in range(1,5):
for d in range(1,5):
count += 1
x = str(x) ; y = str(y) ; d = str(d)
grade.append(list(zip(x,y,d)))
#for each in grade:
#print(each)
print('排列个数为:%d' % count , '内容如下：\n')
print(grade)
运行结果如下：
排列个数为:64 内容如下：
[[('1', '1', '1')], [('1', '1', '2')], [('1', '1', '3')], [('1', '1', '4')], [('1', '2', '1')], [('1', '2', '2')], [('1', '2', '3')], [('1', '2', '4')], [('1', '3', '1')], [('1', '3', '2')], [('1', '3', '3')], [('1', '3', '4')], [('1', '4', '1')], [('1', '4', '2')], [('1', '4', '3')], [('1', '4', '4')], [('2', '1', '1')], [('2', '1', '2')], [('2', '1', '3')], [('2', '1', '4')], [('2', '2', '1')], [('2', '2', '2')], [('2', '2', '3')], [('2', '2', '4')], [('2', '3', '1')], [('2', '3', '2')], [('2', '3', '3')], [('2', '3', '4')], [('2', '4', '1')], [('2', '4', '2')], [('2', '4', '3')], [('2', '4', '4')], [('3', '1', '1')], [('3', '1', '2')], [('3', '1', '3')], [('3', '1', '4')], [('3', '2', '1')], [('3', '2', '2')], [('3', '2', '3')], [('3', '2', '4')], [('3', '3', '1')], [('3', '3', '2')], [('3', '3', '3')], [('3', '3', '4')], [('3', '4', '1')], [('3', '4', '2')], [('3', '4', '3')], [('3', '4', '4')], [('4', '1', '1')], [('4', '1', '2')], [('4', '1', '3')], [('4', '1', '4')], [('4', '2', '1')], [('4', '2', '2')], [('4', '2', '3')], [('4', '2', '4')], [('4', '3', '1')], [('4', '3', '2')], [('4', '3', '3')], [('4', '3', '4')], [('4', '4', '1')], [('4', '4', '2')], [('4', '4', '3')], [('4', '4', '4')]]
z1446773686 发表于 2018-2-6 11:19
count = 0
grade = []
for x in range(1,5):
count = 0
for x in range (1,5):
for y in range (1,5):
for d in range (1,5):
if ((x != y) and ((y != d)and (x != d))):
count += 1
print(x,y,d)
#for each in grade:
#print(each)
print ('排列个数为:%d' % count )