这道题要正面刚才有意思
def fun10(n):
for x in range(1,10000):
y=x
for _ in range(n):
x=x/2-1
if x==1:print(y)
fun10(10)
x1,x2 = 0,1
for each in range(9,0,-1):
x1 = (x2+1)*2
x2 = x1
print("第%d天树上有%d个桃子"%(each,x2))
def chi(n):
i,j = 1,1
while i <= n:
j = (j+1)*2
i += 1
print("第一天总共摘了",j,"个桃子")
i = 1
sum = 1
for i in range(1,11):
sum = (sum+1)*2
i +=1
print(sum)
i = 1
sum = 1
for i in range(1,10):
sum = (sum+1)*2
i += 1
print(sum)
>>> n=1
>>> for i in range(10):
n=2*(n+1)
i=i+1
print(n)
4
10
22
46
94
190
382
766
1534
3070
看下答案
恶大大是、
totalApple = 1
day = 10
leftApple = 1
for i in range(9):
totalApple = (totalApple + 1 ) * 2
print(totalApple)
sum = 1
i = 0
while i < 10:
sum = 2*(sum+1)
i += 1
print(sum)
{:10_333:}
L =
def fun10:
for i in range(9):
a = L
L.append(2*(a+1))
print(L)
print('The totall peach is %s'% (L))
学习了
a = 9
b = 1
while a != 0:
b = (b+1)*2
a -= 1
print(b)
i=1
n=9
while n:
i=(i+1)*2
n-=1
print(i)
last_one = 1
for i in range(9):
last_one = (last_one + 1) * 2
print(last_one)
peaches = * 10
for i in range(8,-1,-1):
peaches = (peaches + 1)*2
print(f'第一天共摘了{peaches}个桃.')
print(f'每天早上剩的桃子数为:{peaches}.')
#第十天还没开吃,所以其实一共吃了9次
x = 1
for i in range(9):
x = (x+1) * 2
print("猴子第一天一共有%s个桃子"%x)
学习!
num = 1
for i in range(0,10):
num += 1
num *= 2
print(num)