Python：每日一题 10

fan1993423

这道题要正面刚才有意思

1. def fun10(n):
   
2.     for x in range(1,10000):
   
3.             y=x
   
4.             for _ in range(n):
   
5.                 x=x/2-1
   
6.             if x==1:print(y)
   
7. fun10(10)
   

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克里斯保罗

x1,x2 = 0,1
for each in range(9,0,-1):
          x1 = (x2+1)*2
          x2 = x1
          print("第%d天树上有%d个桃子"%(each,x2))

阿瑞

def chi(n):
    i,j = 1,1
    while i <= n:
        j = (j+1)*2
        i += 1
    print("第一天总共摘了",j,"个桃子")

Msathmi

i = 1
sum = 1
for i in range(1,11):
    sum = (sum+1)*2
    i +=1
print(sum)

Msathmi

i = 1
sum = 1
for i in range(1,10):
    sum = (sum+1)*2
    i += 1
print(sum)

九五二七

>>> n=1
>>> for i in range(10):
        n=2*(n+1)
        i=i+1
        print(n)

       
4
10
22
46
94
190
382
766
1534
3070

1752633745

看下答案

Jdradon

恶大大是、

javen7

totalApple = 1
day = 10
leftApple = 1

for i in range(9):
    totalApple = (totalApple + 1 ) * 2
print(totalApple)

积极向上的小刘

sum = 1
i = 0
while i < 10:
    sum = 2*(sum+1)
    i += 1
print(sum)

mmmer

Jung

L = [1]
def fun10:
    for i in range(9):
        a = L[i]
        L.append(2*(a+1))
    print(L)
    print('The totall peach is %s'% (L[len(L)-1]))

zhongyong6899

学习了

天下一统2014

a = 9
b = 1
while a != 0:
  b = (b+1)*2
  a -= 1
print(b)

ouyunfu

i=1
n=9
while n:
    i=(i+1)*2
    n-=1
print(i)

Yedada

last_one = 1

for i in range(9):
    last_one = (last_one + 1) * 2

print(last_one)

海上飞鱼

1. peaches = [1] * 10
   
2. for i in range(8,-1,-1):
   
3.     peaches[i] = (peaches[i+1] + 1)*2
   
4. print(f'第一天共摘了{peaches[0]}个桃.')
   
5. print(f'每天早上剩的桃子数为：{peaches}.')

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xiaofan1228

#第十天还没开吃，所以其实一共吃了9次

x = 1
for i in range(9):
    x = (x+1) * 2

print("猴子第一天一共有%s个桃子"%x)

嘿嘿嘿的黑子哥

学习！

uune

1. num = 1
   
2. for i in range(0,10):
   
3.     num += 1
   
4.     num *= 2
   
5. print(num)

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