论坛 › Python交流 › Python：每日一题 78（答题领鱼币）

l1993520 发表于 2017-8-31 05:51:23

kankandashen

疯子的快乐 发表于 2017-9-2 19:54:03

看大神

骚强么么哒 发表于 2017-9-2 20:00:16

围观

克里斯蒂亚诺 发表于 2017-9-4 12:47:38

def average(string):
    nums = str.split(string,' ')
    correspond = ['one','two','three','four','five',
                  'six','seven','eight','nine']
    n_sum = 0
    for each in nums:
      if each in correspond:
            n_sum = n_sum+correspond.index(each)+1
      else:
            return 'n /a'
    a_num = n_sum/len(nums)
    return correspond
   
if __name__=='__main__':
    e_num = input('input your english numbers:')
    result = average(e_num)
    print(result)
   

lihuayuan 发表于 2017-9-11 19:32:02

不知道

谱写未来 发表于 2017-9-12 08:46:41

看看答案

总有理 发表于 2017-9-16 11:34:10

n/a 不大会做，其他的代码用for循环打了一下
def average_string(str1):
        num = {'zero':0,'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7,'eight':8,'nine':9}
        list1=[]
        for i in num:
                if i in str1:
                        list1.append(num.get(i))
        average = 0
        for i in list1:
                average+=i
        average = average/len(list1)
        return average

py交易老李 发表于 2017-9-24 19:49:20

{:5_91:}

胡先生 发表于 2017-9-26 09:59:39

看看大神

shigure_takimi 发表于 2017-12-4 17:13:21

def average_string(string):
    english = ['zero','one','two','three','four','five','six','seven','eight','nine']
    newList =
    numberList = []
    for word in newList:
      if word in english:
            numberList.append(english.index(word))
      else:
            print('n / a')
            return None
    print(english)

average_string('one three two')
average_string('five five five')
average_string('ku fthj two')

lebroncm 发表于 2017-12-8 19:05:43

def average_string(i):
    sum=0
    a=['zero','two','one','three','four','five','six','seven','eight','nine']
    b=
    d=dict(zip(a,b))
    e=i.split()
    for each in e:
      if each in a:
            sum=sum+d
      else:
            return 'n/a'
    return sum/len(e)

凌九霄 发表于 2018-3-31 23:40:14

本帖最后由 凌九霄 于 2018-3-31 23:44 编辑

def average_string(s):
    stringN = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
    num = 0
    i = 0
    lst = s.split(" ")
    for x in lst:
      if x in stringN:

            num += stringN.index(x)
            if num > 9 :
                return 'n/a'
                break
            i += 1
      else:
            return 'n/a'
    return stringN

DavidCowboy 发表于 2018-8-17 16:56:33

def average_string(x,y,z):
    list1 = ['zero','one','two','three','four','five','six','seven','eight','nine']
    while x in list1 and y in list1 and z in list1:
      sum1 = list1.index(x) + list1.index(y) + list1.index(z)
      return sum1
    else:
      print('n/a')

子沙 发表于 2018-8-18 13:17:00

def average_string(num):
    num=str(num)
    list_num=['zero','one','two','three','four','five','six','seven','eight','nine']
    m=0
    n=0
    for i in list_num:
      p=num.count(i)
      m+=p*list_num.index(i)
      n+=p
      num=num.replace(i,'')
    k=0
    if num.count(' ')==len(num):
      print(list_num)
    else:
      print('n/a')
average_string('one two six')
average_string('dad six')

小木子c 发表于 2018-8-18 16:51:05

观摩

兀颜光 发表于 2018-8-21 13:43:42

啊啊啊所

jiaozhu80 发表于 2018-8-27 20:07:05

本帖最后由 jiaozhu80 于 2018-8-27 20:10 编辑

def average_atring(string):
    m={"one":1,"two":2,"three":3,"four":4,"five":5,"six":6,"seven":7,"eight":8,
      "nine":9,"zero":0}
    list1=string.split()
    sum=0
   
    for a in list1:
      if a in m.keys():
   
            sum+=m.get(a)
      else:
            return "n/a"
    average=int(sum/len(list1))
    for key,value in m.items():
      if average == value:
            average=key
    return average
      

gx112345 发表于 2018-8-28 12:08:06

不相同的地方，很多很多

咕咕鸡鸽鸽 发表于 2019-2-26 15:44:19

dict1 = {"zero":0,
      "one":1,
         "two":2,
         "three":3,
         "four":4,
         "five":5,
         "six":6,
         "seven":7,
         "eight":8,
         "nine":9}


def fun78(str1):
    list1 = str1.split(" ")
    list2 = []
    for each in list1:
      try:
            temp = dict1
      except:
            return "n / a"
      list2.append(temp)

    avg = sum(list2) // (len(list2))
    for key,value in dict1.items():
      if avg == value:
            return key

print(fun78("one nine two"))
print(fun78("one ten two"))

哇嘎哩恭 发表于 2019-2-26 16:24:23

1

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