index=('zero','one','two','three','four','five','six','seven','eight','nine')
def average_string(string):
try:string=string.split(' ');return index
except:return'n / a'
哇哇哇我竟然和大神解法一样！好激动！
def average_string(string:str):
dict_num ={'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7}
total =[]
temp = string.split(' ')
count = 0
for each in temp:
if each not in dict_num:
return 'n/a'
else:
total.append(dict_num)
count+=1
a = sum(total)//count
return ''.join()
看大神
def f_78(string):
lst = ['zero', 'one', 'two', 'three', 'four',
'five', 'six', 'seven', 'eight', 'nine']
key = string.split(' ')
try:
return lst) / len(key))]
except ValueError:
return "n/a"
print(f_78('one three two'))
学习一下
很好
想看回帖
本帖最后由 楽叁 于 2020-3-15 00:23 编辑
import re
dicts = (‘zero’,'one', 'two', 'three', 'four', 'five',
'six', 'seven', 'eigth', 'night')
string = 'one three two'
string1 = 'five five five'
string2 = 'ku fthj two'
string3 = 2
def average_string(strs):
if type(strs) != str:
return '请输入英文数字，以空格隔开'
strs = strs.strip()
strs_list = re.findall(r'\w+', strs)
acount = 0
for num in strs_list:
if num not in dicts:
return 'n / a'
else:
acount += dicts.index(num)
nums = int(acount / len(strs_list))
return dicts
print(average_string(string))
# 输入字符串以空格分隔，转化为列表
# 新建一个字典，英文字符串为键，阿拉伯数字为值。
# 转化英文数字字符串为阿拉伯数字，求平均数。
import numpy as np
def average_string(st_num):
st_num_list = st_num.split(' ')
num_dic = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4,'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9}
st_num_trans = if i in num_dic.keys() else i for i in st_num_list]
for j in st_num_trans:
if str(j).isalpha():
return "'n/a'"
else:
ave = np.mean(st_num_trans)
return ave
#st_num = input('请输入英文数字字符串: ')
st_num = 'one three two'
print(average_string(st_num))
1
看看
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