Python：每日一题 78（答题领鱼币）

永恒的蓝色梦想

1. index=('zero','one','two','three','four','five','six','seven','eight','nine')
   
2. def average_string(string):
   
3.         try:string=string.split(' ');return index[sum((index.index(i)for i in string))//len(string)]
   
4.         except:return'n / a'

复制代码

永恒的蓝色梦想

哇哇哇我竟然和大神解法一样！好激动！

克里斯保罗

def average_string(string:str):
    dict_num ={'one':1,'two':2,'three':3,'four':4,'five':5,'six':6,'seven':7}
    total =[]
    temp = string.split(' ')
    count = 0
    for each in temp:
        if each not in dict_num:
            return 'n/a'
        else:
            total.append(dict_num[each])
            count+=1
    a = sum(total)//count
   
    return ''.join([k for (k,v) in dict_num.items() if v == a])

XiaoPaiShen

看大神

Geoffreylee

1. def f_78(string):
   
2.     lst = ['zero', 'one', 'two', 'three', 'four',
   
3.            'five', 'six', 'seven', 'eight', 'nine']
   
4. 
   
5.     key = string.split(' ')
   
6.     try:
   
7.         return lst[int(sum([lst.index(i) for i in key]) / len(key))]
   
8.     except ValueError:
   
9.         return "n/a"
   
10. 
    
11. 
    
12. print(f_78('one three two'))

复制代码

kkk999de

学习一下

Frozen83

很好

毅行者。。

想看回帖

楽叁

1. import re
   
2. 
   
3. dicts = (‘zero’,'one', 'two', 'three', 'four', 'five',
   
4.          'six', 'seven', 'eigth', 'night')
   
5. string = 'one three two'
   
6. string1 = 'five five five'
   
7. string2 = 'ku fthj two'
   
8. string3 = 2
   
9. 
   
10. 
    
11. def average_string(strs):
    
12.     if type(strs) != str:
    
13.         return '请输入英文数字，以空格隔开'
    
14.     strs = strs.strip()
    
15.     strs_list = re.findall(r'\w+', strs)
    
16.     acount = 0
    
17.     for num in strs_list:
    
18.         if num not in dicts:
    
19.             return 'n / a'
    
20.         else:
    
21.             acount += dicts.index(num)
    
22. 
    
23.     nums = int(acount / len(strs_list))
    
24.     return dicts[nums]
    
25. 
    
26. 
    
27. print(average_string(string))
    

复制代码

holiday_python

# 输入字符串以空格分隔，转化为列表
# 新建一个字典，英文字符串为键，阿拉伯数字为值。
# 转化英文数字字符串为阿拉伯数字，求平均数。
import numpy as np

def average_string(st_num):
    st_num_list = st_num.split(' ')
    num_dic = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4,'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9}
    st_num_trans = [num_dic[i] if i in num_dic.keys() else i for i in st_num_list]
    for j in st_num_trans:
        if str(j).isalpha():
            return "'n/a'"
    else:
        ave = np.mean(st_num_trans)
        return ave

#st_num = input('请输入英文数字字符串: ')
st_num = 'one three two'
print(average_string(st_num))

19971023

1

z2x2c8

看看

aironeng

学习