[已解决]Python：每日一题 338

def f338(lst):
    t = set("qwertyuiop")
    m = set("asdfghjkl")
    l = set("zxcvbnm")
    n = []
    for i in lst:
        k = set(i.lower())
        if k & t == k or k & m == k or k & l == k:
            n.append(i)
    return n

def p338(lst):        
    al = set("qwertyuiop"),set("asdfghjkl"),set("zxcvbnm")
    return [lst[i] for i in range(len(lst)) for j in al if set(lst[i].lower()) <= j]

def p338(lst):
    return [lst[i] for i in range(len(lst)) for j in [set("qwertyuiop"),set("asdfghjkl"),set("zxcvbnm")] if set(lst[i].lower()) <= j]

def fun338(strArr):
    Keyboard = []
    Keyboard.append('QqWwEeRrTtYyUuIiOoPp')
    Keyboard.append('AaSsDdFfGgHhJjKkLl')
    Keyboard.append('ZzXxCcVvBbNnMm')
    def inWhich(character):
        for i in range(0,3):
            if character in Keyboard[i]:
                return i
    def isWordOk(word):
        try:
           state = inWhich(word[0])
        except Exception:
            return False
        for each in set(word):
            if each not in Keyboard[state]:
                return False
        return True
    result = []
    for eachWord in strArr:
        if isWordOk(eachWord):
            result.append(eachWord)
    return result