关于md5加密程序的问题
S1E30 指针函数和函数指针的课后作业，动动手第0题原题：
答案代码如下：
#include <stdio.h>
#include <string.h>
#include "md5.h"
void md5(unsigned char *dest, unsigned char *src);
void md5(unsigned char *dest, unsigned char *src)
{
int i;
MD5_CTX md5;
// 初始化
MD5Init(&md5);
// 传入明文字符串及其长度
MD5Update(&md5, src, strlen((char *)src));
// 得到加密后的字符串
MD5Final(&md5, dest);
}
int main(void)
{
int i;
unsigned char src;
unsigned char dest;
printf("请输入密码：");
scanf("%s", src);
printf("你输入的密码是：%s\n", src);
md5(dest, src);
printf("加密后的密码是：");
for (i = 0; i < 16; i++)
{
printf("%02x", dest);
}
putchar('\n');
return 0;
}
但是我运行后却这样子：
加密的内容不见了？请问是怎么回事？
已把程序与头文件放在同一目录，附上头文件代码：
md5.h
#ifndef MD5_H
#define MD5_H
typedef struct
{
unsigned int count;
unsigned int state;
unsigned char buffer;
}MD5_CTX;
#define F(x,y,z) ((x & y) | (~x & z))
#define G(x,y,z) ((x & z) | (y & ~z))
#define H(x,y,z) (x^y^z)
#define I(x,y,z) (y ^ (x | ~z))
#define ROTATE_LEFT(x,n) ((x << n) | (x >> (32-n)))
#define FF(a,b,c,d,x,s,ac) \
{ \
a += F(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define GG(a,b,c,d,x,s,ac) \
{ \
a += G(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define HH(a,b,c,d,x,s,ac) \
{ \
a += H(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
#define II(a,b,c,d,x,s,ac) \
{ \
a += I(b,c,d) + x + ac; \
a = ROTATE_LEFT(a,s); \
a += b; \
}
void MD5Init(MD5_CTX *context);
void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputlen);
void MD5Final(MD5_CTX *context,unsigned char digest);
void MD5Transform(unsigned int state,unsigned char block);
void MD5Encode(unsigned char *output,unsigned int *input,unsigned int len);
void MD5Decode(unsigned int *output,unsigned char *input,unsigned int len);
#endif 没人来吗{:10_250:}
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