请问为啥识别小写字母的时候会3和9之间有的识别不出。。还有最后为啥结果是个空列...
def temp(str1):list1 = []
zimu ='qwertyuiopasdfghjklzxcvbnm'
zimu1 ='QWERTYUIOPASDFGHJKLZXCVBNM'
a = 0
b = 0
time1 = 0
for each in str1:
if each in zimu:
b = str1.index(each,a)
a = b+1
print (each,end=',')
print (b)
for each1 in str1[(b-3):(b+4)]:
if each1 in zimu1:
time1 +=1
if time1 == 3:
list1.append(each)
print (list1) 1 这代码是准备干啥的 wp231957 发表于 2021-6-1 10:44
这代码是准备干啥的
用来在字符串里面找密码的题。。a) 每位密码为单个小写字母Powered by bbs.fishc.com
b) 每位密码的左右两边均有且只有三个大写字母j~ 本帖最后由 淡淡凉 于 2021-6-2 11:53 编辑
for each1 in str1[(b-3):(b+4)]:
if each1 in zimu1:
time1 +=1
if time1 == 3:
list1.append(each)
你的条件为只有time1==3才往列表列表里添加元素，因为不符合条件所以就没有添加到列表，列表为空，所以打印的列表为空；你可以试试把条件改为time<=3,符合条件成功添加后还要重置time1=0
def temp(str1):
list1 = []
zimu ='qwertyuiopasdfghjklzxcvbnm'
zimu1 ='QWERTYUIOPASDFGHJKLZXCVBNM'
a = 0
b = 0
for each in str1:
time1 = 0
if each in zimu:
b = str1.index(each,a)
a = b+1
print (each,end=',')
print (b,end='\t')
#print(str1[(b-3 if b-3>0 else 0):(len(str1) if b+4>len(str1) else b+4)])
list2 = []
str2 = str1[(b-3 if b-3>0 else 0):(len(str1) if b+4>len(str1) else b+4)]
for each1 in str2:
if each1 in zimu1:
list2.append(each1)
time1 +=1
print(str2+'共出现大写字母的次数：',time1,list2)
if time1 <= 3:
list1.append(each)
print (list1)
temp('PoWErEDbybbs.FishC.com')
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