求帮助 循环问题 急急急
Assume if we don't have either break or else-on-loop statement available, how do we need to modify the code above? ~~ Write a code without break and else-on-loop statements to do the same work.假设如果我们没有break或else on循环语句可用，我们需要如何修改下面的代码？
for n in range(2, 10):
for x in range(2, n):
if n % x == 0:
print(n, 'equals', x, '*', n//x)
break
else:
# loop fell through without finding a factor
print(n, 'is a prime number')
# end for n in range(2, 10):
c = 0
for x in range(2, n):
if n % x == 0:
print(n, 'equals', x, '*', n//x)
c += 1
if not c : print(n, 'is a prime number') jackz007 发表于 2022-10-21 15:31
谢谢大佬 钢镚航 发表于 2022-10-21 15:48
谢谢大佬
如果问题解决了，不要忘记上"最佳答案" 哦
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