修改代码
void deleteEmployee() {int id;
printf("请输入要删除的员工工号:");
scanf("%d", &id);
Employee* current = head;
Employee* prev = NULL;
Employee* temp = NULL;
while (current != NULL) {
if (current->id == id) {
if (prev == NULL) {
head = current->next;
} else {
prev->next = current->next;
}
temp = current;
current = current->next;
free(temp);// 释放删除的节点
printf("员工信息删除成功!\n");
break;
}
prev = current;
current = current->next;
}
_save(head);// 将更新后的链表保存到文件中
}
如果只有一个员工,结果上面这段代码实现无法删除,而我想要他删除,怎么修改 要删除链表中只有一个员工的情况,可以在循环之后增加一段代码来判断链表是否为空,并进行相应的处理。以下是修改后的代码:
void deleteEmployee() {
int id;
printf("请输入要删除的员工工号:");
scanf("%d", &id);
Employee* current = head;
Employee* prev = NULL;
Employee* temp = NULL;
while (current != NULL) {
if (current->id == id) {
if (prev == NULL) {
head = current->next;
} else {
prev->next = current->next;
}
temp = current;
current = current->next;
free(temp);// 释放删除的节点
printf("员工信息删除成功!\n");
break;
}
prev = current;
current = current->next;
}
if (head == NULL) {
printf("当前员工列表已为空!\n");
}
_save(head);// 将更新后的链表保存到文件中
}
这样,在删除员工之后,如果链表为空,则会输出提示信息"当前员工列表已为空!"。这样就可以正常删除链表中只有一个员工的情况了。
以上回复来自 FishC AI 小助理,如未能正确解答您的问题,请继续追问。 如果只有一个员工,你可以使用 while 循环条件来遍历链表,当找到要删除的节点时,则将其从链表中删除。
以下是修改后的代码:
void deleteEmployee() {
int id;
printf("请输入要删除的员工工号:");
scanf("%d", &id);
Employee* current = head;
Employee* prev = NULL;
while (current != NULL) {
if (current->id == id) {
if (prev == NULL) {
head = current->next;
} else {
prev->next = current->next;
}
break;
}
prev = current;
current = current->next;
}
if (current == NULL) {
printf("没有找到工号为 %d 的员工!\n", id);
} else {
_save(head);// 将更新后的链表保存到文件中
printf("员工信息删除成功!\n");
}
}
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