表达式求值问题 大家帮我看看代码问题出错在哪里
#include <stdio.h>#include <ctype.h>
#include <stdlib.h>
#define STACK_INIT_SIZE 20
#define STACKINCREMENT10
#define MAXBUFFER 10
typedef char ElemType;
typedef struct
{
ElemType *base;
ElemType *top;
int stackSize;
}sqStack;
InitStack(sqStack *s)
{
s->base = (ElemType *)malloc(STACK_INIT_SIZE * sizeof(ElemType));
if( !s->base )
exit(0);
s->top = s->base;
s->stackSize = STACK_INIT_SIZE;
}
Push(sqStack *s, ElemType e)
{
// 栈满,追加空间,
if( s->top - s->base >= s->stackSize )
{
s->base = (ElemType *)realloc(s->base, (s->stackSize + STACKINCREMENT) * sizeof(ElemType));
if( !s->base )
exit(0);
s->top = s->base + s->stackSize;
s->stackSize = s->stackSize + STACKINCREMENT;
}
*(s->top) = e; // 存放数据
s->top++;
}
int StackLen(sqStack s)
{
return (s.top - s.base);
}
Pop(sqStack *s, ElemType *e)
{
if( s->top == s->base )
return;
*e = *--(s->top); // 将栈顶元素弹出并修改栈顶指针
}
int jisuan(char ss)
{
sqStack s;
int i= 0,j = 0;
double d, e;
char str;
int i = 0;
InitStack( &s );
while( ss != '#' )
{
while( isdigit(ss) || ss=='.' )// 用于过滤数字
{
str = ss;
str = '\0';
if( i >= 10 )
{
printf("出错:输入的 个数据过大!\n");
return -1;
}
if( ss == ' ' )
{
d = atof(str);
Push(&s, d);
i = 0;
break;
}
}
switch( ss )
{
case '+':
Pop(&s, &e);
Pop(&s, &d);
Push(&s, d+e);
break;
case '-':
Pop(&s, &e);
Pop(&s, &d);
Push(&s, d-e);
break;
case '*':
Pop(&s, &e);
Pop(&s, &d);
Push(&s, d*e);
break;
case '/':
Pop(&s, &e);
Pop(&s, &d);
if( e != 0 )
{
Push(&s, d/e);
}
else
{
printf("\n出错:除数为零!\n");
return -1;
}
break;
}
j++;
}
Pop(&s, &d);
printf("\n最终的计算结果为:%f\n", d);
return 0;
}
int main()
{
sqStack s;
char c, e;
int i = 0;
char ss;
InitStack( &s );
printf("请输入中缀表达式,以#作为结束标志:");
scanf("%c", &c);
while( c != '#' )
{
while( c>='0' && c<='9' )
{ ss = c;
printf("%c", c);
scanf("%c", &c);
if( c<'0' || c>'9' )
{
printf(" ");
ss = ' ';
}
}
if( ')' == c )
{
Pop(&s, &e);
while( '(' != e )
{ ss = e;
printf("%c ", e);
Pop(&s, &e);
}
}
else if( '+'==c || '-'==c )
{
if( !StackLen(s) )
{
Push(&s, c);
}
else
{
do
{
Pop(&s, &e);
if( '(' == e )
{
Push(&s, e);
}
else
{ ss = e;
printf("%c ", e);
}
}while( StackLen(s) && '('!=e );
Push(&s, c);
}
}
else if( '*'==c || '/'==c || '('==c )
{
Push(&s, c);
}
else if( '#'== c )
{
break;
}
else
{
printf("\n出错:输入格式错误!\n");
return -1;
}
scanf("%c", &c);
}
while( StackLen(s) )
{
Pop(&s, &e);
printf("%c ", e);
ss = e;
}
ss = '\0';
printf("输出后缀表达式!");
printf("%s",ss);
jisuan(ss);
return 0;
}
下面是错误提示
incompatible types - from 'double *' to 'char *' char str;
改为
char *str; 答案
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