if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else{
bill = cost * flag;}
if (ibex > 14)
{
sheds = 3;
}
sheds = 2;
else
{
help = 2 * sheds;
}
1
1
加油
快乐
0.100个
1.10个
2.a
3.??????
4.x > 0 && z = x || x < 0 && z = -x
5.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
0. 100
1. 10
2. a, b, c
3. a = 14, b = 5, c = 9
4. z = x>=0?sqrt(x):0
5.if (size > 12) {
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
5.1. if (ibex > 14){
sheds = 3;
}
sheds = 2
help = 2 * sheds;
5.2. while (score < 0){
printf("count = %d\n", count);
count++
scanf("%d", &score);
}
5.3 #include <stdio.h>
int main(int argc, char *argv[]) {
int score = 0, count = 0;
while (1) {
scanf("%d", &score);
if (score < 0) {
printf("count=%d\n", count);
return 0;
}
count++;
}
return 0;
}
0. #include <stdio.h>
int main(int argc, char *argv[]) {
float start = 10000;
float c_total = start, h_total = start;
float s_rate = 0.1, c_rate = 0.05;
int count;
while (c_total >= h_total) {
c_total += start * s_rate;
h_total = h_total * (1 + c_rate);
count++;
}
printf("%d年后, 黑夜超过小甲鱼!", count);
printf("小甲鱼投资额度: %.2f\n", c_total);
printf("黑夜投资额度: %.2f\n", h_total);
return 0;
}
1. #include <stdio.h>
int main(int argc, char *argv[]) {
float money = 400, spend = 50;
float rate = 0.08;
int count;
while (money >= 0) {
money -= spend;
money += money * rate;
count++;
}
printf("%d年之后, 破产...", count);
return 0;
}
2.
3. 2^(n-1) 求和
q
0.10个A
1.9个B
2.c
3.b=5,c=9
4.x>0?x:|x|
5.
666
0
....
6666666666666
DA
1
答案
0:10个
1:10个
2:a
3:a = 14,b = 3,c = 9
0:#include <stdio.h>
int main()
{
int a = 10000, b = 10000, year = 0;
float i = a, j = b;
while(i >= j)
{
i = i + a * 0.1;
j = j * (1 + 0.05);
year++;
}
printf("%d年后,黑夜的投资额超过小甲鱼!\n", year);
printf("小甲鱼的投资额是:%.2f\n", i);
printf("黑夜的投资额是:%.2f\n", j);
return 0;
}
1:#include <stdio.h>
int main()
{
int a = 4000000, b = 500000, year = 1;
float i = a - b;
while (i > 0)
{
year++;
i = i * (1 + 0.08) - b;
}
printf("%d年后,小甲鱼败光了所有的家产,再次回到一贫如洗!\n", year);
return 0;
}
2:#include <stdio.h>
#include <math.h>
int main()
{
int i = 1, j = 1, n = 2;
float pi = 1;
while(fabs(j) > pow(10, -8))
{
if(n % 2 == 0)
{
i = -(i + 2);
}
else
{
i = i + 2;
}
j = 1 / i;
pi = pi + j;
n++;
}
printf("Π= %.7f", pi);
return 0;
}
学习
0.10
1.0
2
3.b=4,c=10
4.z=x>0?x:-x
5.if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
1