一时学习一时爽
发表于 2021-9-26 18:52:34
学习
武sdd
发表于 2021-9-27 18:36:00
0.10
1.0
2
3.b=4,c=10
4.z=x>0?x:-x
5.if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
else
{
bill = cost * flag;
}
Ais0329
发表于 2021-9-27 20:32:36
1
林小尖
发表于 2021-9-27 22:06:02
吧
redHmian
发表于 2021-9-27 22:40:19
{:5_109:}
Lauren-
发表于 2021-9-27 23:25:40
.
zhuangzitao
发表于 2021-9-28 11:19:56
#include <stdio.h>
int main(void)
{
int year;
float xiaojiayu = 10000.0f, heiye = 10000.0f;
for (year = 1; heiye <= xiaojiayu; year++) {
xiaojiayu += 10000 * 0.1;
heiye *= 1.05;
}
printf("%d年后,黑夜的投资额超过小甲鱼!\n", year);
printf("小甲鱼的投资额是: %.2f\n", xiaojiayu);
printf("黑夜的投资额是: %.2f\n", heiye);
return 0;
}
#include <stdio.h>
int main(void)
{
int year;
float money = 4000000.0f;
for (year = 1; money >= 0.0f; year++) {
money -= 500000.0f;
money *= 1.08;
}
printf("%d年之后,小甲鱼败光了所有的家产,再次回到一贫如洗......", year);
return 0;
}
#include <stdio.h>
#include <math.h>
int main(void)
{
double sum = 0.0;
int i = 1;
int temp = pow(10, 8);
int count = 1;
while ( fabs(i) <= temp) {
if(count % 2 == 0)
i = -i;
sum += 1.0 / i;
i = fabs(i) + 2;
count++;
}
printf("π的值为:%.7f", sum * 4);
return 0;
}
#include <stdio.h>
int main(void)
{
int sum = {1, 1}, i;
for(i = 3; i < 24; i++) {
sum = sum + sum;
printf("现在有%d对兔子。\n", sum);
}
printf("两年之后可以繁殖%d对兔子。\n", sum);
return 0;
}
冲啊yongyong
发表于 2021-9-28 16:18:06
1
冲啊yongyong
发表于 2021-9-28 16:18:43
呃呃呃
944789838
发表于 2021-9-28 19:08:40
朕想知道
gxd666
发表于 2021-9-29 09:33:04
1
xydrain
发表于 2021-9-29 15:09:50
1
gxd666
发表于 2021-9-29 15:26:54
1
豆芽菜丶
发表于 2021-9-29 18:22:15
0、10
1、0
2、a.b.c
3、a=14,b=5,c=9
4、
#include <stdio.h>
int main()
{
int x=-5, z;
z = x < 0 ? -x : x;
printf("%d",z);
return 0;
}
5、
#include <stdio.h>
int main()
{
int size, cost, bill, flag;
if (size > 12)
{
cost = cost * 1.05;
}
flag = 2;
bill = cost * flag;
return 0;
}
B、
if (ibex > 14)
sheds = 3;
else
sheds = 2;
help = 2 * sheds;
C、
do{
scanf("%d", &score);
count++;
} while (score > 0);
printf("count = %d\n", count-1);
动动手
0、
int years = 0;
float count1 = 10000, count2 = 10000;
do
{
years++;
count1 += 1000 * years;
count2 += count2 * 0.05;
} while(count2<count1);
printf("%d年后,黑夜的投资额超过了小甲鱼!\n", years);
printf("小甲鱼的投资额是:%0.2f\n", count1);
printf("黑夜的投资额是%0.2f\n", count2);
return 0;
1、
int years = 0;
float count = 4000000;
do
{
years++;
count -= 500000;
count += count*0.08;
} while(count>0);
printf("%d年后,小甲鱼败光了所以的家产,再次回到一贫如洗......\n", years);
return 0;
2、
double i = 1, count = 0, pi;
while (fabs(1 / i) > pow(10, -8))
{
count += 1 / i;
i = -i;
if (i < 0)
i -= 2;
else
i += 2;
}
pi = count * 4;
printf("%lf", pi);
3、
LeaflLit
发表于 2021-10-1 15:39:12
0.100
1.9
2.
3.a=14,b=4,c=8
4.z=(int)sqrt(double x*x)
5.
梦回汉唐
发表于 2021-10-1 17:38:59
验证代码
软大头
发表于 2021-10-2 15:28:34
asdasdasdasd
muoushi
发表于 2021-10-2 21:21:59
1
一只学C的萌新
发表于 2021-10-3 10:44:55
我是越来越搞不懂for语句了
putuo3
发表于 2021-10-3 13:55:11
46368