10个
1.
0个
2.
a, b, c
3.
a = 14; b = 5; c = 9;
4.
z = x >= 0 ? x : -x;
5.
A.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B.
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;
C.
while (1)
{
scanf("%d", &score);
if (score < 0)
{
break;
}
count++;
}
printf("count = %d\n", count);
0.
10个
1.
0个
2.
a, b, c
3.
a = 14; b = 5; c = 9;
4.
z = x >= 0 ? x : -x;
5.
A.
if (size > 12)
{
cost = cost * 1.05;
flag = 2;
}
bill = cost * flag;
B.
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
}
help = 2 * sheds;
C.
while (1)
{
scanf("%d", &score);
if (score < 0)
{
break;
}
count++;
}
printf("count = %d\n", count);
动动手
0.
#include <stdio.h>
#define PRINCIPAL 10000
int main()
{
float principal1 = PRINCIPAL, principal2 = PRINCIPAL;
int year;
for (year = 0; principal1 >= principal2; year++)
{
principal1 += PRINCIPAL * 0.1;
principal2 *= 1 + 0.05;
}
printf("%d年后 , 黑夜的投资额超过小甲鱼!\n小甲鱼的投资额是 : %.2f\n黑夜的投资额是 : %.2f\n", year, principal1, principal2);
return 0;
}
1.
#include <stdio.h>
int main ()
{
int year;
float money = 400;
for (year = 0; money > 0; year++)
{
money -= 50;
money *= 1.08;
}
printf("%d年之后 , 小甲鱼败光了所有的家产 , 再次回到一贫如洗......\n", year);
return 0;
}
2.
#include <stdio.h>
#include <math.h>
int main()
{
double sum = 0, num = 1.0;
do
{
sum += num;
}while (fabs(num = -1.0/(num < 0 ? 1.0/num - 2 : 1.0/num + 2)) >= pow(10, -8));
printf("%.7f", 4 * sum);
return 0;
}
3.
#include <stdio.h>
int main()
{
int a = 1, b = 1, temp;
for (int i = 2; i < 24; i++)
{
temp = b;
b = a + b;
a = temp;
}
printf("两年后可以繁殖%d次\n", b);
return 0;
} s 。。。 1 000 0. 10个
1. 0 个
2.
3.a = 9, b = 3, c = 9
4.
A
if (size > 12)
{
cost = cost * 1.05;
flag = 2;;
}
else
{
bill = cost * flag;
}
B
if (ibex > 14)
{
sheds = 3;
}
else
{
sheds = 2;
help = 2 * sheds;
}
C
if (score < 0)
{
printf("count = %d\n", count);
}
else
{
count++;
scanf("%d", &score);
}
.
打卡
333 0.81 1.10 2.a 3.a=30 b=3 c=9 4.? 看看答案
1 查看参考答案 ,