【Python学习笔记】统计字母数字空格等个数

def count_para(*param):

    coun = 0

    for i in param:

        coun += 1

        num = 0; alph = 0; space = 0; other = 0

        for j in list(i):

             asc = ord(j)

             if 47<asc<58: num += 1

             elif 64<asc<91 or \

                  96<asc<123: alph += 1

             elif asc == 32: space += 1

             else:other += 1

        print 'The no.',coun,'string has',num,'number,',\

              alph,'letter,',space,'space and',other,'other letter.'