[已解决]怎么统计这个文件中出现频率排前10的整数。（代码）

isdkz

1. from operator import itemgetter
   
2. import random
   
3. 
   
4. # 生成文件
   
5. with open('data.txt', 'w') as fp:
   
6.     lst = (str(random.randint(0,20))+'\n' for _ in range(1200))
   
7.     fp.writelines(lst)
   
8. 
   
9. # 统计文件
   
10. with open('data.txt') as fp:
    
11.     result = {}
    
12.     for line in fp:
    
13.         temp = int(line[:-1])
    
14.         result[temp] = result.get(temp, 0) + 1
    
15.     result = dict(sorted(result.items(), key=itemgetter(1,0), reverse=True))
    
16.     for k, v in tuple(result.items())[:10]:
    
17.         print(f'随机数：{k}, 出现次数：{v}')

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