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发表于 2023-4-3 21:03:51
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本楼为最佳答案
- # coding: utf-8
- def split_n_k(n, k):
- """
- 将正整数 n 划分成 k 个正整数之和的划分数目
- """
- if n < k:
- return 0
- if n == k:
- return 1
- # 动态规划
- dp = [[0] * (n + 1) for _ in range(k + 1)]
- for i in range(1, k + 1):
- for j in range(i, n + 1):
- if i == 1:
- dp[i][j] = 1
- else:
- dp[i][j] = dp[i - 1][j - i] + dp[i][j - i]
- return dp[k][n]
- def split_diff(n):
- """
- 将正整数 n 划分成若干个不同正整数之和的划分数目
- """
- dp = [0] * (n + 1)
- dp[0] = 1
- for i in range(1, n + 1):
- for j in range(n, i - 1, -1):
- dp[j] += dp[j - i]
- return dp[n]
- def split_odd(n):
- """
- 将正整数 n 划分成若干个奇正整数之和的划分数目
- """
- # 这里的代码和上面的 split_diff 函数也很相似
- dp = [0] * (n + 1)
- dp[0] = 1
- for i in range(1, n + 1, 2):
- for j in range(i, n + 1):
- dp[j] += dp[j - i]
- return dp[n]
- while True:
- try:
- n, k = map(int, input().split())
- print(split_n_k(n, k))
- print(split_diff(n))
- print(split_odd(n))
- except:
- break
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