题目65：找出e的连分数中第100个收敛项的分子各位之和。

fc1735

1. from fractions import Fraction
   
2. 
   
3. def fun(n):
   
4.   if n == 0:
   
5.     return 2
   
6.   elif n % 3 == 2:
   
7.     return (n + 1) * 2 // 3
   
8.   else:
   
9.     return 1
   
10. 
    
11. ans = Fraction(0)
    
12. for i in map(lambda x: fun(x), reversed(range(100))):
    
13.   ans += i
    
14.   ans = 1 / ans
    
15. 
    
16. print(sum(map(lambda x: int(x), str(ans.denominator))))
    

复制代码

https://github.com/devinizz/project_euler/blob/master/page02/65.py