Python：每日一题 149

nononoyes

list = [0,1,2,3,4,5,6,7,8,9]
lenresult = len(list)//3
k=2
n=0
newlist = [0,1,2,3,4,5,6,7,8,9]
while(len(list)>1):
    for i in range(lenresult):
        newlist.remove(list[3*i+k])
    n = (len(list)+n)%3
    list = newlist[:]
    k = 2-n
    lenresult = (len(list)+n)//3
print('最后留下来的数字是：',newlist)

最后留下来的数字是： [3]