[已解决]在函数中怎么访问entry中的内容

jackz007

1. import tkinter as tk
   
2. from tkinter.filedialog import askopenfilename
   
3. from tkinter.messagebox import *
   
4. 
   
5. def select_com():
   
6.     etyText . set(askopenfilename())
   
7. 
   
8. def run_com():
   
9.     filePath = etyText.get()
   
10.     showinfo('Tips', filePath)
    
11. 
    
12. def win_tk():
    
13.     global etyText                          # 添加此句，把 etyText 置为全局变量
    
14.     root = tk.Tk()
    
15.     root.attributes('-alpha', 0.9)
    
16.     root.geometry('700x200+400+200')
    
17.     etyText = tk.StringVar()
    
18.     lb = tk.Label(root, font=('Arial', 10), text=' File Path :')
    
19.     ety = tk.Entry(root, font=('Arial', 10), textvariable=etyText, width=80)
    
20.     btnSelect = tk.Button(root, font=('Arial', 10), text='  Select  ', command=select_com)
    
21.     btnRun = tk.Button(root, font=('Arial', 10), fg='white', bg='gray', text='   Run   ', command=run_com)
    
22. 
    
23.     lb.grid(row=0, column=0)
    
24.     ety.grid(row=0, column=1)
    
25.     btnSelect.grid(row=0, column=2)
    
26.     btnRun.grid(row=1, column=1)
    
27.     tk.mainloop()
    
28. 
    
29. if __name__ == '__main__':
    
30.     win_tk()

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